MHB Clearing a Vertical Wall: Solving for Height with Right Angle Trig

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An airplane ascends from a station at a 10-degree angle to the horizontal. The problem involves determining how high the airplane will be when it reaches a vertical wall that is 100 feet high and 900 feet away. Using the tangent function, the height of the airplane at that distance is calculated to be approximately 58.69 feet. This means the airplane will not clear the wall, as it will be 41.31 feet below the top of the wall. The discussion emphasizes the application of right-angle trigonometry to solve the problem.
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An airplane starts from a station and rises at an angle of 10 deg with the horizontal. By how many feet will it clear a vertical wall 100 ft. High and 900 ft from the station?

I don't get it. Can you provide an image that represent the situation in the problem. Thanks.
 
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paulmdrdo said:
An airplane starts from a station and rises at an angle of 10 deg with the horizontal. By how many feet will it clear a vertical wall 100 ft. High and 900 ft from the station?

I don't get it. Can you provide an image that represent the situation in the problem. Thanks.

ok ... View attachment 3417
 
Thanks!

My solution

$\tan10^{\circ}=\frac{100'+h}{900'}$h = 58.69 ft.
 
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