Clebsch-Gordan coefficients (l+1/2)

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SUMMARY

The discussion centers on the calculation of Clebsch-Gordan coefficients for the addition of orbital angular momentum and spin 1/2, specifically the expression &langle m-1/2,1/2|l+1/2,m &rangle = \sqrt{\frac{l+m+1/2}{2l+1}}. The user initially misapplied the ladder operator J_+ and derived an incorrect expression that yielded values greater than unity. Upon further reflection, the user identified their mistake and acknowledged the correct formulation presented in Sakurai's textbook, which emphasizes the proper application of the ladder operator in this context.

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Daviddc

Homework Statement


I was going through Sakurai's textbook and I tried to work out by myself the following expression for the Clebsch-Gordan coefficients (Addition of orbital angular momentum and spin 1/2)

\begin{equation}
\langle m-1/2,1/2|l+1/2,m \rangle = \sqrt{\frac{l+m+1/2}{2l+1}}
\end{equation}

Homework Equations



\begin{equation}
J_{\pm} |jm \rangle=\sqrt{(j \mp m)(j \pm m +1)} \\
J_{i,\pm} |m_1 m_2 \rangle=\sqrt{(j_i \mp m_i)(j_i \pm m_i +1)}
\end{equation}

The Attempt at a Solution



\begin{equation}
|l+1/2,m \rangle = \sum_{m'} \left[|m'-1/2,1/2\rangle \langle m'-1/2,1/2|l+1/2,m \rangle + |m'+1/2,-1/2\rangle \langle m'+1/2,-1/2|l+1/2,m \rangle \right]
\end{equation}

Aplying J_+

\begin{equation}
\sqrt{(l+1/2-m)(l+1/2+m+1)}|l+1/2,m+1 \rangle = \sum_{m'} \left[\sqrt{(l-m'+1/2)(l+m'-1/2+1)}|m'+1/2,1/2\rangle \langle m'-1/2,1/2|l+1/2,m \rangle + \sqrt{(1/2+1/2)(1/2-1/2+1)} |m'+1/2,+1/2\rangle \langle m'+1/2,-1/2|l+1/2,m \rangle +\sqrt{(l-m'-1/2)(l+m'+1/2+1)}(|m'+3/2,-1/2\rangle \langle m'+1/2,-1/2|l+1/2,m \rangle \right]
\end{equation}

Taking the inner product \begin{equation} \langle m+1/2, 1/2 | \end{equation}

\begin{equation}
\sqrt{(l+1/2-m)(l+1/2+m+1)} \langle m+1/2,1/2 | l+1/2, m+1 \rangle = \sqrt{ (l-m+1/2)(l+m+1/2)} \langle m-1/2,1/2 | l+1/2, m \rangle
\end{equation}

\begin{equation}
\langle m-1/2,1/2 | l+1/2, m \rangle=\sqrt{\frac{l+m+3/2}{l+m+1/2}} \langle m+1/2,1/2 | l+1/2, m+1 \rangle
\end{equation}

Aplying the ladder operator until m reaches its maximum value (i.e. l+1/2),

\begin{equation}
\langle m-1/2,1/2 | l+1/2, m \rangle=\sqrt{\frac{2l+1}{l+m+1/2}}
\end{equation}

As you can see, I obtain the answer upside down. It is obviously wrong since you get values larger than the unity. In Sakurai's textbook he starts with this:

\begin{equation}
\sqrt{(l+1/2-m)(l+1/2+m+1)} \langle m-1/2,1/2 | l+1/2, m \rangle = \sqrt{ (l-m+1/2)(l+m+1/2)} \langle m+1/2,1/2 | l+1/2, m+1 \rangle
\end{equation}

But I don't understand why it is like that instead of the one I derived. I'm sure that my mistake is something stupid, but I can't find it and it is pissing me off since it's 1 am and I didn't have dinner yet because of this. If any of you can point out where I am failing I will be thankful.

Thank you for your time.
 
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Oh, I have just realized where my mistake is...

Thank you anyways.
 

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