Closed Subsets and Limits of Sequences: A Topology Book Example

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SUMMARY

The discussion centers on the concept of closed subsets in topology, specifically addressing the cocountable topology where every set is closed under limits of sequences, yet not all sets are closed. Participants clarify that while every closed set is closed under limits of sequences, the converse is not true. An example provided is the set of positive real numbers in the cocountable topology, which demonstrates a set that is sequentially closed but not closed. The terminology of sequentially closed sets and sequential spaces is also highlighted.

PREREQUISITES
  • Understanding of basic topology concepts, including closed sets and limits of sequences.
  • Familiarity with cocountable topology and its properties.
  • Knowledge of nets and their relation to sequences in topological spaces.
  • Awareness of first-countable spaces and their characteristics.
NEXT STEPS
  • Study the properties of cocountable topology in detail.
  • Explore the concept of nets and their applications in topology.
  • Learn about first-countable spaces and their implications in topology.
  • Read "Topology" by Wilansky to understand closed sets and limits of sequences further.
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Mathematicians, topology students, and educators seeking to deepen their understanding of closed sets and limits in topological spaces.

Fredrik
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Anyone have a good example of a closed subset of a topological space that isn't closed under limits of sequences?
 
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Hi Frederik! :smile:

Every closed set of a topological space is closed under limits of sequences! It's the converse that's not true. That is: there are sets which are not closed but which are still closed under limits of sequences.

For example, take the cocountable topology. Let X be a set and set

\mathcal{T}=\{A\subseteq X~\vert~X\setminus A~\text{is countable}\}\cup\{\emptyset\}

Every convergent sequence in this topology is (eventually) a constant sequence. Thus all sets are closed under limits of sequences. But not all sets are closed, of course.

Some terminology: a set that is closed under limits of sequences is called sequentially closed. A topological space where closed is equivalent with sequentially closed, is called a sequential space. As is well-known, all first-countable spaces are sequential.
 
micromass said:
Hi Frederik! :smile:
Hi. I actually laughed out loud when I went back here after only ten minutes and saw that you had already replied. :smile: It's appreciated, as always. (I had to go out for a while after that. I would have replied sooner otherwise).

micromass said:
Every closed set of a topological space is closed under limits of sequences! It's the converse that's not true.
Ah yes. I actually had that right in my mind a few minutes earlier, but somehow got it wrong anyway when I made the post. This is what I was thinking before my IQ suddenly dropped 50 points: In a metric space, a set is closed if and only if it's closed under limits of sequences. In a topological space, the corresponding statement is that a set is closed if and only if it's closed under limits of nets. Since sequences are nets, a closed set must be closed under limits of sequences. These statements suggest that there's a set E that's closed under limits of sequences and still isn't closed. Then there should exist a convergent net in E, that converges to a point in Ec. That's the sort of thing I originally meant to ask for an example of, but your example illustrates the point as well.

micromass said:
\mathcal{T}=\{A\subseteq X~\vert~X\setminus A~\text{is countable}\}\cup\{\emptyset\}

Every convergent sequence in this topology is (eventually) a constant sequence. Thus all sets are closed under limits of sequences.
It took me a while to understand this, but I get it now. It's a good example. It's a weird topology since even 1/n→0 is false in this topology. I think I also see an example of the kind I originally had in mind: Consider the cocountable topology on ℝ. Let E be the set of positive real numbers. Let I be the set of all open neighborhoods of 0 that have a non-empty intersection with E. Let the preorder on I be reverse inclusion. For each i in I, choose xi in i. This defines a net in E with limit 0, which is not a member of E.
micromass said:
Some terminology: a set that is closed under limits of sequences is called sequentially closed. A topological space where closed is equivalent with sequentially closed, is called a sequential space. As is well-known, all first-countable spaces are sequential.
Thanks. I wasn't familiar with this terminology.
 
Now that I think of it, your question would actually make an ideal exam question for my topology students :biggrin: So that's one less question I need to come up with. Thanks a lot!
 
Hi micromass, if you remember us talking about topology books in the PF chatroom, this is discussed in the topology book by wilansky: https://www.amazon.com/dp/0486469034/?tag=pfamazon01-20

and the exact same answer/example is given too, with the cocountable topology and how every sequence would have to be eventually constant. ( it's cool! )
Not that I'm contributing much to the conversation, but I just wanted to point that out
 
wisvuze said:
Hi micromass, if you remember us talking about topology books in the PF chatroom, this is discussed in the topology book by wilansky: https://www.amazon.com/dp/0486469034/?tag=pfamazon01-20

and the exact same answer/example is given too, with the cocountable topology and how every sequence would have to be eventually constant. ( it's cool! )
Not that I'm contributing much to the conversation, but I just wanted to point that out

It's too bad that I can't seem to find that book anywhere :frown: I've looked around for it, because I really want to read it. (I'm actually interested in the exercises)
 
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