Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Co-finite topology on an infinite set

  1. Feb 5, 2012 #1

    Deveno

    User Avatar
    Science Advisor

    If τ is the co-finite topology on an infinite set X, does there exist an injection from τ to X? i'm having trouble wrapping my mind around this.

    on the one hand, for A in τ, we have A = X - S, for some finite set S. so it seems that there is a 1-1 correspondence:

    A <--> S, of τ with the finite subsets of X.

    so if X were countable, it seems that the set of all finite subsets would also be countable (i could put N into a 1-1 correspondence with the algebraic numbers, for example, and what is an algebraic number but it's associated minimal polynomial, and what is an integral polynomial except a finite sequence of integers (its coefficients)?).

    but if X is uncountably infinite, i don't know if τ is "bigger" than X (it's certainly at least as big). certainly τ is uncountable (since it contains X - {x} for every element x of X). i suspect that it is not, that if we "group" the co-finite sets by the size of their complements, then |τ| = |N|*|X| < |X x X| = |X|. is this true?
     
  2. jcsd
  3. Feb 5, 2012 #2

    morphism

    User Avatar
    Science Advisor
    Homework Helper

    Yup. Coupled with your observation about complements of singletons, this proves that |τ|=|X| if X is infinite.
     
  4. Feb 5, 2012 #3
    To complete the classification, you can see that if X is finite and has n elements, all of its subsets are finite, and there are 2n of them, which is more than n. So there is never a 1-1 correspondence between τ and X in the finite case.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Co-finite topology on an infinite set
  1. Point set topology (Replies: 4)

Loading...