Coefficient Of Kinetic Friction

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SUMMARY

The discussion focuses on calculating the coefficient of kinetic friction (μ) between a hockey puck and ice, given an initial speed of 20.0 m/s and a sliding distance of 115 minutes. The equations used include kinematic equations and energy principles, specifically (1/2)mv² = μmgS. The correct approach involves substituting values into the derived formula to find μ, which is essential for understanding frictional forces in physics.

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  • Understanding of kinematic equations
  • Familiarity with Newton's laws of motion
  • Basic knowledge of friction and its coefficients
  • Ability to manipulate algebraic equations
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Joshw17_15
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A hockey puck on a frozen pond is given an initial speed of 20.0 m/s. If the puck always
remains on the ice and slides 115 min before coming to rest, determine the coefficient of
kinetic friction between the puck and ice.




[v = u + a*t
=> 0 = 20 - a* 115*60
=> a = 20/(115*60)

v^2 - u^2 = 2*a*S
=> S = 400*(115*60)/2*20



(1/2)*m*v^2 = u*m*g*S
=> u = (1/2)*v^2/S*g
=> u = (1/2) * 400/S*9.8

I use these equations and I can't seem to come up with right answer
 
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Joshw17_15 said:
(1/2)*m*v^2 = u*m*g*S
=> u = (1/2)*v^2/S*g
=> u = (1/2) * 400/S*9.8

I use these equations and I can't seem to come up with right answer

This should give the correct answer.

1/2mv2=μmg(115)
 

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