Combination Math Problem: Choosing 5 Balls from 4 Boxes without Restriction

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SUMMARY

The problem involves selecting 5 balls from 4 boxes containing red, blue, yellow, and green balls without any restrictions on color. The total number of combinations can be calculated using the "stars and bars" theorem, which states that the number of ways to distribute n indistinguishable objects (balls) into k distinguishable boxes (colors) is given by the formula C(n+k-1, k-1). For this scenario, the calculation results in C(5+4-1, 4-1) = C(8, 3) = 56 combinations.

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Harmony
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Question Statement
4 boxes each contain a large number of identical balls, those in 1 box are red, those in the 2nd box are blue, those in the 3rd box are yellow and those in the remaining box are green. In how many ways can a set of five balls be chosen? (without restriction)

My thoughts
If the question is asking for the permutation, then the answer is 4^5 (since there is 4 colour and the colour can be repeated)

But the question is asking for combinations. How should I attempt this question? Should I consider cases where all colours are the same/ different, 2 same 3 different...etc.?
 
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Harmony said:
But the question is asking for combinations. How should I attempt this question? Should I consider cases where all colours are the same/ different, 2 same 3 different...etc.?
yes...you can have all of same color , or two of same color and 3 of 3 different colors ans so on
 

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