Combinatorics Problem: Finding Number of Subsets in a Set of Four-Digit Numbers

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SUMMARY

The discussion focuses on calculating the number of subsets in a set of four-digit numbers formed from the digits {1, 2, 3}, ensuring each number contains every digit at least once. The initial calculation presented is 54, derived from the formula 3!*3 + 3*12. Participants clarify that the number of subsets of a set with N elements is 2^N, leading to further exploration of the correct interpretation of subsets in this context.

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Homework Statement


Let X be a set containing all four digit numbers made up of {1,2,3}, where every number contains every digit at lease once. Number of all subsets is:

The Attempt at a Solution



So firs i have to find number of elements in the set:

3!*3 + 3*12 = 54

Now what they mean by subsets? And did i calculated number of elements correctly?
 
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54 seems too many. Pls explain your calculation.
For the second part, if there are N elements in a set, how many subsets does it have?
 
It could be they want to know how many possible subsets of X there are.
i.e. any member of X would be a subset of X of size 1. any pair of members would be a subset size 2, etc.
[haruspex beat me :)]
 
Last edited:

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