Commutator of x and p in quantum mechanics

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SUMMARY

The commutator of position and momentum operators, represented as [x,p]=iħ, is a fundamental aspect of quantum mechanics. While it is not explicitly stated as a postulate in most textbooks, it can be treated as one to derive the momentum operator in position representation and vice versa. The momentum operator is linked to translation invariance and serves as the generator of translations. Canonical quantization employs the Poisson bracket relation {q,p}=1, which transitions to the quantum version [q,p]=iħ, reinforcing the postulate's validity.

PREREQUISITES
  • Understanding of quantum mechanics fundamentals, particularly the role of operators.
  • Familiarity with the concept of commutators and their significance in quantum theory.
  • Knowledge of canonical quantization and Poisson brackets in classical mechanics.
  • Basic grasp of the relationship between translation invariance and momentum operators.
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  • Study the derivation of the momentum operator in position representation using the commutator [x,p]=iħ.
  • Explore canonical quantization techniques and their applications in quantum mechanics.
  • Investigate the role of Noether's theorem in connecting symmetries and conservation laws in physics.
  • Read "Quantum Mechanics: A Modern Development" by Ballentine for a deeper understanding of the algebra of space-time transformations.
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Students and professionals in physics, particularly those specializing in quantum mechanics, theoretical physicists, and researchers exploring the foundations of quantum theory.

rbphysics
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TL;DR
Is it a postulate?
The commutator of [x,p]=i$\hbar$. Is it a postulate? No book state it as postulate of Quantum mechanics. But, I don't see anything more general by which I can derieve this. At elementary level Quantum mechanics, one start with momentum operator in position representation to derieve this. But that would mean to take momentum operator as postulate. But If we take the commutator as postulate one can derieve momentum operator in position representation as well as position operator in momentum repres
 
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rbphysics said:
But that would mean to take momentum operator as postulate.
Momentum is the Noether current associated with translation invariance. The momentum operator is the generator of translations. This is the principle from which the momentum operator follows.

But where does ##\hbar## occur in this? It fixes the units, but its numerical value needs to be measured, or „postulated“ (with respect to your question).
 
Following your interest to find more profound idea in quantum mechanics, Heisenberg and Dirac observed that Poissson Bracket {A,B} which appears in analytic mechanics, especially in Hamilton's equation of motion ( https://en.wikipedia.org/wiki/Poisson_bracket ) has its quantum version
$$ \frac{AB-BA}{i\hbar}$$
With this replacement all the classical mechanics structure becomes available in QM also.
As an example in CM, $$\{x,p\}=1$$ thus in QM
$$ \frac{xp-px}{i\hbar}=1$$
 
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rbphysics said:
TL;DR Summary: Is it a postulate?

The commutator of [x,p]=i$\hbar$. Is it a postulate? No book state it as postulate of Quantum mechanics. But, I don't see anything more general by which I can derive this. At elementary level Quantum mechanics, one start with momentum operator in position representation to derieve this. But that would mean to take momentum operator as postulate. But If we take the commutator as postulate one can derive momentum operator in position representation as well as position operator in momentum repres
A common way to quantize classical systems ("canonical quantization") is indeed to take conjugate variables ##q,p## that follow Poisson bracket relation ##\{q,p\}=1## and swap it by ##[\hat q,\hat p]=i\hbar##. So in this formalism, it is indeed a postulate.
 
rbphysics said:
TL;DR Summary: Is it a postulate?

The commutator of [x,p]=i$\hbar$. Is it a postulate? No book state it as postulate of Quantum mechanics. But, I don't see anything more general by which I can derieve this. At elementary level Quantum mechanics, one start with momentum operator in position representation to derieve this. But that would mean to take momentum operator as postulate. But If we take the commutator as postulate one can derieve momentum operator in position representation as well as position operator in momentum repres
You can take it as a postulate, and together with the algebra of the space-time transformations you can derive Quantum mechanics. See for example the book by Ballentine.
 

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