Commutator Relations; Conjugate Product of a Dimensionless Operator

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SUMMARY

The discussion focuses on the commutator relations involving creation and annihilation operators in quantum mechanics. It establishes that the commutator [A*, A] can be expressed as (2m(h/2∏)ω)^1 multiplied by a combination of terms involving position (x) and momentum (p) operators. The identity [x, p] = -[p, x] is confirmed, leading to the conclusion that [x, p] - [p, x] simplifies to -2[p, x]. The discussion emphasizes the zero commutators [x, x] and [p, p].

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically operator algebra.
  • Familiarity with creation and annihilation operators in quantum field theory.
  • Knowledge of commutation relations and their implications in quantum mechanics.
  • Basic grasp of the concepts of position (x) and momentum (p) operators.
NEXT STEPS
  • Study the derivation of commutation relations in quantum mechanics.
  • Explore the role of creation and annihilation operators in quantum harmonic oscillators.
  • Learn about the implications of commutators in quantum field theory.
  • Investigate the physical significance of the identity [x, p] = -iħ.
USEFUL FOR

Quantum physicists, students of quantum mechanics, and researchers focusing on operator theory and quantum field applications will benefit from this discussion.

lukka
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Consider the following commutator for the product of the creation/annihilation operators;

[A*,A] = (2m(h/2∏)ω)^1 [mωx - ip, mωx + ip] = (2m(h/2∏)ω)^1 {m^2ω^2 [x,x] + imω ([x,p] - [p,x]) + [p,p]}

Since we have the identity;

[x,p] = -[p,x]

can one assume that..

[x,p] - [p,x] = [x,p] - (-[x,p]) = -2[p,x]
 
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That's right.

(And of course [x, x] = [p, p] = 0).
 
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Thanks CompuChip
 

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