Compare Orbital Speeds of Satellites at Different Altitudes

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Homework Help Overview

The discussion revolves around comparing the orbital speeds of satellites at different altitudes above the Earth's surface, specifically at one and two and a half Earth radii. Participants are attempting to apply the formula for orbital speed, v = sqrt(GM/r), where G is the gravitational constant, M is the mass of the Earth, and r is the distance from the center of the Earth.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are discussing the correct interpretation of the distances given in the problem, particularly how to calculate the radius from the center of the Earth based on the altitude above the surface. There are questions about unit conversions and the values used for GM.

Discussion Status

The discussion is active, with participants clarifying the values for GM and the correct radius to use in calculations. There is a mix of approaches being explored, and some participants are questioning the assumptions made regarding the distances and units.

Contextual Notes

There is some confusion regarding the interpretation of "one Earth radius above the surface" and how it translates to the total distance from the center of the Earth. Additionally, participants are addressing discrepancies in the values for GM used in calculations.

lindz.12
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Compare the orbital speeds of satellites that orbit at the following altitudes.
(a) One Earth radius above the surface of the Earth (in km/s)

(b) Two and a half Earth radii above the surface of the Earth.

Here is the equation to be used,

orbital speed is v=(sqrt)(GM/r)
G is the universal gravitational constant
M is the mass of the thing in the middle
r is the distance from the center of the thing in the middle to the center of the thing in orbit.

V=(sqrt) [(6.67E-11)(5.97E24 kg)/ (6378000 m]

...and yet, my answer is incorrect.
 
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Welcome to PF.

Aren't the distances they give you above the surface?

Where is the first Earth radius to get to the surface?
 
Those units will give you an answer in m/s, the question asks for km/s
 
the distances are what i know...

earth's mass is 5.97E24...whereas its radius is 6378 km...

the answer i got in km/s was 249866.38...which is wrong..and idk why.
 
v = sqrt ( GM/r )
gm = 399 000 km3s-2 for earth, r = 6400km

(a) One Earth radius above the surface of the Earth (in km/s)
So r = 2 * Earth radius,
v = sqrt( 399 000/ (2*6400)) km/s =

(b) Two and a half Earth radii above the surface of the Earth.
So r = 2.5 * Earth radius,
v = sqrt( 399 000/ (3.5*6400)) km/s =
 
thank you...but where did you get 399,000? isn't GM 3.98E14??

and also, I'm confused on why the radius is 2 and 3.5...?
 
Last edited:
The question says one Earth radius ABOVE the surface - which is 2 Earth radii from the centre.

GM = 6.674E−11 m^3 kg-^1 s^-2 * 5.97E24 Kg = 3.986 E 14 m^3 s^-2 = 398600 km^3 /s^2

edit - GM comes up a lot in orbital calcs and has an inconveniently large and small value, it's easier to remember that it's about 400,000 (in km and s), or just remember - a bit less than 1/2M (km^3/s^2)
 
Last edited:
thanks.
 

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