C/C++ Compare Smallest and Largest 3-Digit Numbers using Logical Operators

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The discussion centers on defining a 3-digit positive integer in programming, specifically using conditional statements. The initial focus is on ensuring the number is at least 100, leading to the realization that it also needs to be less than or equal to 999 to meet the criteria for a 3-digit number. A participant initially considers excluding specific numbers like 55, 1000, and -4 but recognizes that the solution should instead encompass all non-3-digit and non-positive integers. The consensus emphasizes the importance of correctly defining the range of valid integers rather than just excluding a few specific values.
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num is a 3-digit positive integer, such as 100, 989, or 523, but not 55, 1000, or -4.

For most direct readability, your expression should compare directly with the smallest and largest 3-digit number.

Code:
if ( (num >= 100)<STUDENT CODE> ) { 
  ...
}

so far i came up with
Code:
((num >= 100) && (?))
but i don't know how to write something that represents a 3 digit positive number?

Edit: nevermind. i figured it out to be && (num <= 999)
 
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Oh.
Good call!

Actually, I thought that:
Code:
((num >= 100) && (num != 55) && (num != 1000) && (num != -4))
would also work to satisfy the criteria.
 
by doing so you only eliminate those the three numbers though, right? while in fact what needs to be eliminated is any number that's not 3 digits and not positive.
 
ineedhelpnow said:
by doing so you only eliminate those the three numbers though, right? while in fact what needs to be eliminated is any number that's not 3 digits and not positive.

You're right!
I completely missed that condition.
 
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