Comparing Momentum and Velocity

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SUMMARY

The discussion focuses on comparing the momentum and velocity of a car and a truck that possess the same kinetic energy, with the car's mass being one-fifth that of the truck. The kinetic energy equation, KE = 1/2mv², is applied to derive the relationship between their velocities, leading to the conclusion that the velocity of the car (Vc) is √5 times the velocity of the truck (Vt). The momentum equations, p = mv, are utilized to express the momentum of both vehicles, resulting in the car's momentum (Pc) being Pc = (√5/5)mVt. This establishes a clear mathematical relationship between the two vehicles' momentum and velocity.

PREREQUISITES
  • Understanding of kinetic energy equations (KE = 1/2mv²)
  • Knowledge of momentum equations (p = mv)
  • Basic algebra for manipulating equations
  • Concept of mass and its relationship to velocity in physics
NEXT STEPS
  • Study the derivation of kinetic energy and momentum equations in classical mechanics
  • Explore the implications of mass on velocity and momentum in different physical scenarios
  • Learn about energy conservation principles in collisions
  • Investigate real-world applications of momentum in vehicle dynamics
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the relationship between mass, velocity, and momentum in vehicles.

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Homework Statement



A car and a truck have the same kinetic energy, but the car's mass is one fifth that of the truck. Compare the velocity and momentum of the car with those of the truck.

Homework Equations



KE=1/2mv^2
p=mv

The Attempt at a Solution



I am not really sure what to do here. I tried setting up the Kinetic energy equal to each other, but then the mass and velocity would cancel each other out an I am left with 1/2=1/10. My other method was subtracting the 2 energys, but that doesn't make sense now that I am thinking about it...

Any tips on how to do this?
 
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Call the truck's mass m and the truck's velocity Vt. What would its kinetic energy be? How about the car's kinetic energy? If you set those equal to each other, you'll get the right answer.
 
ideasrule said:
Call the truck's mass m and the truck's velocity Vt. What would its kinetic energy be? How about the car's kinetic energy? If you set those equal to each other, you'll get the right answer.

so... 1/2m(Vt^2)=1/2(1/5m)(Vc^2)
1/2m(Vt^2)=1/10m(Vc^2)
5(Vt^2)=Vc^2
Square root of 5 x Vt = VC?
 
Yes.
 
All right, now in solving for the potential momentum of the car compared with the truck.

using p=mv, I found the momentum of the truck to be Pt=mVt. I rewrote the equation so that Vt=m/Pt.

I then found the momentum of the car to be Pc=1/5m x (√5 x Vt) <-- velocity of the car. I substituted the Vt so that Pc= 1/5m x √5 x mVt. I canceled out the m's, so all I am left with is Pc= √5 x Vt/ 5.
 

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