Comparing thermo dynamic processes

In summary, the problem involves a cylinder with 1.2 mol of ideal gas at 3.60 x10^5 pa and 300k, which is then compressed until the volume is halved. The question asks for the work done on the gas for different compression processes (isothermal, adiabatic, and isobaric) and which process results in the greatest and least change in internal energy. The correct approach for calculating work for the isobaric process is w = p(V2 - V1). The greatest change in internal energy occurs for the isobaric process because the pressure remains constant, while the least change occurs for the isothermal process because the temperature remains constant. In order for the gas to be
  • #1
icelated
8
0

Homework Statement



in a cylinder, 1.2 mol of an ideal gas, gamma = 1.67 initially at 3.60 x10^5 pa
and 300k, is compressed until the volume is halved.

I need help with 1) c
and
2)

Compute work done on the gas if the compression is:

1)

a) isothermal
b) adiabatic
c) isobaric

2) in which case is the absolue value of the change in internal energy of the gas the greatest? least?

Homework Equations



I think i have a and b worked out.

The Attempt at a Solution



for c) would this be the correct approach?

is this part correct?

V1 = ?
V2 = 1/2V1

w = p(V2 - V1)
w = p(1/2v - v)

pv = nrt

w = -1/2nrt?

2) greatest is isobaric because?
least is isothermal because delta u =0 constant temp and temp is related to change in internal energy.
 
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  • #2
How can the gas get compressed if the process is isobaric? What other property must change?
 
  • #3
the volume is being compressed. But, th pressure remains constant so the area of work is less than the other 2 processes? Adiabatic is the most?
 

What is the difference between isothermal and adiabatic processes?

The main difference between isothermal and adiabatic processes is the transfer of heat. In an isothermal process, the temperature remains constant and there is no change in internal energy. In an adiabatic process, there is no exchange of heat with the surroundings and the change in internal energy is due to work done on the system.

How do you determine the efficiency of a thermo dynamic process?

The efficiency of a thermo dynamic process can be determined by calculating the ratio of the work output to the heat input. This is known as the Carnot efficiency and is given by the formula: efficiency = (T1 - T2)/T1, where T1 is the temperature of the heat source and T2 is the temperature of the heat sink.

What is the relationship between entropy and heat transfer in a thermo dynamic process?

The second law of thermodynamics states that the total entropy of a closed system will always increase over time. In a thermo dynamic process, heat transfer plays a crucial role in determining the direction of entropy change. Heat transfer from a high temperature to a low temperature system increases the overall entropy of the system.

How does the first law of thermodynamics apply to comparing thermo dynamic processes?

The first law of thermodynamics states that energy cannot be created or destroyed, only transferred or converted from one form to another. This law applies to comparing thermo dynamic processes as it helps us understand the energy balance of a system and how different processes affect the overall energy of the system.

What is the significance of the P-V diagram in comparing thermo dynamic processes?

The P-V (pressure-volume) diagram is a graphical representation of the changes in pressure and volume of a system during a thermo dynamic process. It is a useful tool for visualizing and comparing different processes, as it allows us to calculate the work done and the heat transferred during a process. The shape and area under the curve on a P-V diagram can also provide insights into the efficiency and reversibility of a process.

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