Compass Behavior Near Parallel Current-Carrying Wires

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In the discussion about the behavior of a compass near two parallel current-carrying wires, it is established that wire A carries current out of the page while wire B carries current into the page. The compass placed 4 cm from wire A will point based on the superposition of the magnetic fields created by both wires. When the currents are in opposite directions, the compass needle experiences a net effect due to the repulsion between the wires' magnetic fields. If the currents are in the same direction, the compass needle will be attracted towards the wires. Understanding the vector sum of the magnetic fields is crucial for determining the compass needle's direction.
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Homework Statement


two wires are parallel to each other,carries current of same magnitude, and the distance between them is 10cm ,, wire A carries current out of the page ,, Wire B carries current into the page ... A compass is placed at 4 cm from wire A .. Where does the needle point ?

I also would like to know where does the needle will point if the two wires carries same current direction

Homework Equations


-
same current direction - Attraction
opposite current direction - Repulsion

The Attempt at a Solution


I drew the magnetic field around each wire(Wire A-Anticlockwise ... Wire B-Clock wise) , but since the field is circular around a straight wire , so I couldn't know where it will point exactly .
 
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Samurai44 said:
I drew the magnetic field around each wire(Wire A-Anticlockwise ... Wire B-Clock wise) , but since the field is circular around a straight wire , so I couldn't know where it will point exactly .
It will be tangent to the circle at any location around the circle.
 
gneill said:
It will be tangent to the circle at any location around the circle.
so the other wire won't affect the direction of the needle unless the compass was at mid point ?
 
Samurai44 said:
so the other wire won't affect the direction of the needle unless the compass was at mid point ?
No, the fields from both wires will sum at any given location (superposition principle). Pick a location and sketch the circles centered on each wire that pass though that point. Sketch in the field vector at that point for each wire. Sum the vectors.
 
gneill said:
No, the fields from both wires will sum at any given location (superposition principle). Pick a location and sketch the circles centered on each wire that pass though that point. Sketch in the field vector at that point for each wire. Sum the vectors.
alright thanks
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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