afrano said:
All the books I read just say that the set of number states (n) forms a complete space. They just say that the sum of all the ket-bra of states n (over all possible n) is equal to unity.
I am having trouble proving this. Can anyone direct me to a good proof and/or show me the way?
Just to clarify: Are you asking how to prove that the sum of ket-bra of states n is equal to unity? Or is it more that you know how to show that the sum is equal to unity, but want to know how this proves that the states are complete?
If you're after the former then Messiah volume 1 has a good section round about chapter XII section 3,4 and 5. There's quite a lot of material to summarise, but if you can't get hold of the book, I'd be happy to do my best if someone else can't come up with something succinct.
If you're after the latter, then if we assume that the basis u_i is complete we have:
[tex]|\psi>= \sum_{i=1}^{n}|u_i > <u_i|\psi>[/tex] (decomposition)
Which is the same thing as
[tex]|\psi>= \sum_{i=1}^{n}(|u_i > <u_i|)|\psi>[/tex]
Thus the sum over the ket-bra must equal unity/identity. I'm not sure this proves that the sum of ket-bra can only equal unity for a complete set though. Merely that for a complete set, the sum is unity.EDIT:
https://www.physicsforums.com/showthread.php?t=173896
This thread seeks to answer the question, though I'll admit it's a little convoluted.