Complex Analysis: Largest set where f(z) is analytic

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SUMMARY

The discussion focuses on determining the largest set D where the function f(z) = Log(iz+1) / (z^2+2z+5) is analytic and finding its derivative. The key points include identifying that iz+1 is not in the interval (-∞,0] and recognizing that the denominator z^2+2z+5 is zero at z = ±1-2i. The incomplete solution suggests that D = C \ {±1-2i} and emphasizes the importance of the real part restriction for the logarithm. The derivative is discussed, with references to the product and quotient rules, highlighting that the derivative of Log(z) is 1/z.

PREREQUISITES
  • Complex analysis fundamentals
  • Understanding of analytic functions
  • Knowledge of logarithmic functions in the complex plane
  • Familiarity with differentiation rules, specifically product and quotient rules
NEXT STEPS
  • Study the properties of analytic functions in complex analysis
  • Learn about the principal branch of logarithmic functions in complex variables
  • Explore the application of the product and quotient rules in complex differentiation
  • Investigate the implications of branch cuts in complex functions
USEFUL FOR

Students of complex analysis, mathematicians working with analytic functions, and anyone interested in understanding the behavior of logarithmic functions in the complex plane.

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Homework Statement


Find the largest set D on which f(z) is analytic and find its derivative. (If a branch is not specified, use the principal branch.)

f(z) = Log(iz+1) / (z^2+2z+5)

Homework Equations

The Attempt at a Solution


Not sure how to even attempt this solutions but I wrote down that
iz+1 ∉ (-∞,0]. This is where I get confused! Not sure if I have to put z in x+iy form.

For the denominator, z^2+2z+5 ≠ 0 implies z = +/- 1-2i.

So my incomplete solution would be D = C\ { +/- 1-2i } υ { ?? } and the derivative is 1/(iz+1)?
 
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For the log, the restriction is on the real part.
For your derivative, it seems like you lost the contribution from the denominator.
 
RUber said:
For the log, the restriction is on the real part.
For your derivative, it seems like you lost the contribution from the denominator.

Okay, so if it's just the real part, iz+1 = i(x+iy) + 1 = ix - y +1 so the restriction would just be -y+1, where y ≠ 1?

I'm unsure what to do for a derivative, in my class notes it states that [log z ]' = 1/z so would it include the whole f(z) function, ie. ((z^2 + 2z + 5) / (iz+1))
 
This would be either the product rule or the quotient rule.
##[\frac{g(z)}{f(z)}]'= \frac{fg'-gf'}{[f(z)]^2}##
 

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