Compound Angle Formula for Trig Functions

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The discussion revolves around using the compound angle formula for trigonometric functions to simplify the expression sin(pi/4)cos(pi/12) + cos(pi/4)sin(pi/12). Participants clarify that this expression can be rewritten as sin(pi/4 + pi/12), which simplifies to sin(pi/3). The user struggles with calculating sin(pi/12) and cos(pi/12) due to their relation to special triangles. They seek assistance in fully solving for these values to complete the expression. The conversation emphasizes the importance of understanding the application of the compound angle formula in trigonometry.
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Homework Statement



hello i am having trouble with a question here it is

use an appropriate compound angle formula to express a a single trig formula than determine an exact formula for each

a) sin pi/4 cos pi/12 +cos pi/4 sin pi/12

so i got most of it i put it into the fourmla sin(x+y)=sinxcosx+cosysinx

i solved for the right side and got square root of 3 over 2
but for the left side i am having trouble relating pi/12 to a special triangle as it is only 15
so far i am only able to do
sin pi/4 cos pi/12 + cos pi/4 sin pi/12
1/sq root of2 + blank+1/sq of root 2 + blank

as you can see i can solve the cos pi/12 and sin pi/12 if some one could please help me and show full steps as there is the same numbers for the diff compound formulas so i can see how to solve those
thank you
 
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I have no idea what you are doing!
The question looks like you have to use sin(A + B) to simplify the expression given.

In which case it's just sin(pi/4 + pi/12).
which is sin(pi/3)
 
zycismia said:

Homework Statement



hello i am having trouble with a question here it is

use an appropriate compound angle formula to express a a single trig formula then determine an exact formula for each

a) sin pi/4 cos pi/12 +cos pi/4 sin pi/12

so i got most of it i put it into the formula sin(x+y)=sinxcosx+cosysinx

i solved for the right side and got square root of 3 over 2
but for the left side i am having trouble relating pi/12 to a special triangle as it is only 15
so far i am only able to do
sin pi/4 cos pi/12 + cos pi/4 sin pi/12
1/sq root of2 + blank+1/sq of root 2 + blank

as you can see i can solve the cos pi/12 and sin pi/12 if some one could please help me and show full steps as there is the same numbers for the diff compound formulas so i can see how to solve those
thank you
Hello zycismia. Welcome to PF !

That should be: (1/(sq root of 2)) (times) blank1 + (1/(sq of root 2)) (times) blank2 .
 

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