- #1
harlowz2
- 2
- 0
1. Sample calculation - If a satellite carrying a magnetometer flies at 300km over a current that is flowing at 100km w/ a magnitude of 150 μA/m2 (over a cross-section of ~5 km2), how big a ΔB will be seen by the magnetometer?
Assumptions (based on my understanding):
-Satellite altitude remains constant
-Current altitude and magnitude remains constant
-Speed of the satellite does not matter
Knowns:
Current density (Amps/m2) = J = 150
Distance between magnetometer and current = r = 200 km
Current area = Area = 5 km2
2. I have very limited experience with magnetic field calculations, but I believe the equation that should be used is as follows (note: instructor did not provide any equation):
A form of the Biot-Savart Law ⇔ B= (μ0/4[itex]\pi[/itex]) * [itex]\int[/itex](J x r)/r2 d[itex]\upsilon[/itex]
3. I do not have an attempt at a solution, since I have no idea where to start. Please help!
UPDATE: Here is what I have tried so far, and the units appear to check out.
Using a scalar form of the Biot-Savart Law, and assuming a unit depth for the volume integral, I get...
B = (μ0/4[itex]\pi[/itex]) * (J * Area)/r2
After plugging numbers in, I arrive at: ΔB = 1.1111*10-12 T = 1.110 pT
Is this anywhere close, or even sound right? I have the tendency to pull ideas out of thin air.
Thanks,
Zack
Assumptions (based on my understanding):
-Satellite altitude remains constant
-Current altitude and magnitude remains constant
-Speed of the satellite does not matter
Knowns:
Current density (Amps/m2) = J = 150
Distance between magnetometer and current = r = 200 km
Current area = Area = 5 km2
2. I have very limited experience with magnetic field calculations, but I believe the equation that should be used is as follows (note: instructor did not provide any equation):
A form of the Biot-Savart Law ⇔ B= (μ0/4[itex]\pi[/itex]) * [itex]\int[/itex](J x r)/r2 d[itex]\upsilon[/itex]
3. I do not have an attempt at a solution, since I have no idea where to start. Please help!
UPDATE: Here is what I have tried so far, and the units appear to check out.
Using a scalar form of the Biot-Savart Law, and assuming a unit depth for the volume integral, I get...
B = (μ0/4[itex]\pi[/itex]) * (J * Area)/r2
After plugging numbers in, I arrive at: ΔB = 1.1111*10-12 T = 1.110 pT
Is this anywhere close, or even sound right? I have the tendency to pull ideas out of thin air.
Thanks,
Zack
Last edited: