MHB Computer Company's Break Even Point: 30000 Computers

  • Thread starter Thread starter Suraphel
  • Start date Start date
  • Tags Tags
    Break even Point
AI Thread Summary
The computer company plans to produce 30,000 computers at a selling price of $700 each, with fixed costs of $5,000,000 and total variable costs of $6,000,000. To find the break-even point, the total revenue must equal the sum of fixed and variable costs. The break-even point occurs when revenue from selling the computers matches the total costs, which is calculated as revenue = number of computers sold x selling price. Clarification is sought on the calculation process, with a request for a final answer. The discussion emphasizes understanding the break-even formula rather than simply providing the answer.
Suraphel
Messages
4
Reaction score
0
Dear All,
Please help me.
A computer company plans to produce 30000 computer next year. They will sell for \$700 each. The fixed cost of operation care \$5000000 total variable cost are \$6000000. What is the break even point?
 
Last edited by a moderator:
Mathematics news on Phys.org
at the break even point, revenue - (fixed cost + variable cost) = 0

You are given both fixed and total variable costs ... revenue is number of computers sold time \$700
 
skeeter said:
at the break even point, revenue - (fixed cost + variable cost) = 0

You are given both fixed and total variable costs ... revenue is number of computers sold time \$700

A little bit confused please put the final answer.
Thanks in advance.
 
Suraphel said:
A little bit confused please put the final answer.
Thanks in advance.
What are you confused about? Please let us know.. It'll give us a better idea about how to respond. We are not going to simply post the answer though you have essentially been give the solution already.

-Dan
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
For original Zeta function, ζ(s)=1+1/2^s+1/3^s+1/4^s+... =1+e^(-sln2)+e^(-sln3)+e^(-sln4)+... , Re(s)>1 If we regards it as some function got from Laplace transformation, and let this real function be ζ(x), that means L[ζ(x)]=ζ(s), then: ζ(x)=L^-1[ζ(s)]=δ(x)+δ(x-ln2)+δ(x-ln3)+δ(x-ln4)+... , this represents a series of Dirac delta functions at the points of x=0, ln2, ln3, ln4, ... , It may be still difficult to understand what ζ(x) means, but once it is integrated, the truth is clear...
Back
Top