Computing the action for a particle in a gravitational field

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SUMMARY

The discussion centers on computing the classical action S for a particle of mass m in a gravitational field described by the potential U = -α/r. The classical action is defined as S = ∫(t_i to t_f) L(q, \dot{q}, t) dt, where the Lagrangian L is given by L = (1/2) m \dot{\mathbf{r}}^2 + (α/r). The integration of this expression requires knowledge of the trajectory r(t), which is not provided, leading to the conclusion that the integral cannot be computed without further information about r(t).

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  • Understanding of classical mechanics and Lagrangian dynamics
  • Familiarity with the concept of action in physics
  • Knowledge of gravitational potential energy
  • Basic calculus skills for performing integrals
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  • Study the derivation of the Lagrangian for different potential fields
  • Learn techniques for solving integrals involving variable limits
  • Explore the concept of trajectory in gravitational fields
  • Investigate the application of variational principles in classical mechanics
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Students in physics, particularly those studying classical mechanics, as well as educators preparing for oral examinations in this subject area.

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A friend of mine told me he fielded this at an oral exam: "Compute the classical action [itex]S[/itex] for a particle of mass [itex]m[/itex] in a gravitational field [itex]U = -\alpha/r[/itex]." I know the formula for the classical action is given by

[tex] S = \int_{t_i}^{t_f} L(q,\dot q,t) dt,[/tex]

and that for a particle in a gravitational field, we have

[tex] L = \frac 12 m \dot{\mathbf{r}}^2 + \frac{\alpha}{r}[/tex]

(where, of course, [itex]|\mathbf{r}| = r[/itex]) so that

[tex] S = \int_{t_i}^{t_f} \left( \frac 12 m \dot{\mathbf{r}(t)}^2 + \frac{\alpha}{r(t)} \right) dt.[/tex]

But how in the WORLD am I supposed to perform this integration? Am I supposed to derive expressions for [itex]\mathbf{r}[/itex] and [itex]r[/itex] as functions of [itex]t[/itex]?
 
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Wow...well, I guess I don't feel so bad about not having been able to do this now!
 
You don't know who r(t) is, so you can't compute the integral, can you ? I think your last expression is exactly what the problem/examinator asked for. So A^+, huh ? :D
 

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