Calculating Maximum Silver Plating from AgNO3 Solution

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SUMMARY

The maximum amount of silver that can be plated from 4.6 L of an AgNO3 solution with 3.7% Ag by mass is determined using the solution's density of 1.01 g/mL. First, calculate the total mass of the solution (4.6 L = 4600 mL, thus mass = 4600 mL * 1.01 g/mL = 4646 g). Then, apply the mass percent formula to find the mass of silver: (3.7/100) * 4646 g = 171.58 g. Therefore, 171.58 grams of silver can be plated from the solution.

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  • Understanding of mass percent calculations
  • Basic knowledge of solution density
  • Familiarity with moles and solute-solvent relationships
  • Ability to perform unit conversions (L to mL, g to kg)
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  • Explore stoichiometry related to silver nitrate reactions
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Homework Statement



Silver nitrate solutions are often used to plate silver onto other metals. What is the maximum amount of silver (in grams) that can be plated out of 4.6 L of an AgNO3 solution containing 3.7% Ag by mass? Assume that the density of the solution is 1.01g/mL .


Homework Equations


m=moles of solute/ mass of solvent (kg)
mass percent=(mass of component/ total mass of solution)*100%


The Attempt at a Solution


I have no idea how to even approach this problem so maybe just a hint can help me gain some sort of insight.
 
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Start finding mass of the solution, then apply percentage information.
 
Thank you so much, I figured it out and got it right. :smile:
 

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