Concentration of the resulting solution in this question

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SUMMARY

The discussion focuses on calculating the concentration of a hydrochloric acid (HCl) solution after boiling and removing a specific mass of HCl. Initially, 1 liter of N/5 HCl is boiled down to 250 mL, resulting in a concentration change. After removing 3.65 grams of HCl, participants suggest calculating the remaining moles of HCl and the new volume to determine the updated molarity and normality of the solution.

PREREQUISITES
  • Understanding of molarity and normality calculations
  • Knowledge of moles and mass conversions
  • Familiarity with hydrochloric acid properties
  • Basic principles of solution concentration changes
NEXT STEPS
  • Calculate the molarity of HCl before and after boiling
  • Determine the moles of HCl removed using the formula: moles = mass/molar mass
  • Learn how to calculate new concentration after volume changes
  • Explore the relationship between molarity and normality for strong acids
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Chemistry students, laboratory technicians, and anyone involved in solution preparation and concentration calculations will benefit from this discussion.

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Homework Statement


On boiling 1litre N/5 HCl, the volume of the aqueous solution decreases to 250mL. If 3.65g of HCl is removed from the solution then the concentration of resulting solution becomes?


Homework Equations


No idea, from where should i start
 
Physics news on Phys.org
1. Molarity of HCl?

2. Moles of HCl removed?

3. New volume?

You will have moles of HCl left in solution, new volume after boiling, so you can find out new molarity, and by extension, new Normality.
 

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