How Do You Calculate Equilibrium Concentrations in a Redox Reaction?

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SUMMARY

The discussion centers on calculating equilibrium concentrations in the redox reaction between Fe2+ and Cr2O72-, represented by the equation: 6Fe2+ + Cr2O72- + 14H+ > 6Fe3+ + 2Cr3+ + 7H2O. The equilibrium constant for this reaction is 1×1057. Participants expressed confusion regarding the concentrations of Cr3+ and Fe3+ at equilibrium, particularly in relation to the initial concentrations of K2Cr2O7 and FeSO4 solutions. Clarifications were made regarding dilution effects and the need to adjust initial concentrations when calculating equilibrium states.

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cliffordlim
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Homework Statement


Fe2+and Cr2O72- react as follows: 6Fe2+ + Cr2O7 2− + 14H + >>> 6Fe3+ + 2Cr3+ + 7H2O.

The equilibrium constant for the reaction is 1×10^57. Calculate the equilibrium concentrations

of the iron and chromium species if 10 mL each of 0.02M K2Cr2O7 in 1.14M HCl and 0.12M FeSO4

in 1.14M HCl are reacted.

Homework Equations




The Attempt at a Solution


https://physicsforums-bernhardtmediall.netdna-ssl.com/data/attachments/97/97696-2f7ec586395970f64d734682baf6f166.jpg

This is the solution provided . I still don't understand as Cr3+ is 0.02M in the equation as the question give is K2Cr2O7 is 0.02M > does it mean 0.02M of Cr2O72- ? Same goes to iron .
 

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cliffordlim said:
I still don't understand as Cr3+ is 0.02M in the equation as the question give is K2Cr2O7 is 0.02M > does it mean 0.02M of Cr2O72-

Elaborate please, I have no idea what you mean.

Chances are you are forgetting about dilution, but that's just a wild guess.
 
I think there is a mistake in the text; when it says "At equilibrium 0.02 mol/L Cr2O72- has reacted..." that should be 0.01 mol/L Cr2O72-. Is that the problem? I think the expression here is unclear. But then you say "same goes to iron". Are you just forgetting about dilution, as Borek suggests?
 

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