Concentrations of conjugate bases at specific pH levels

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SUMMARY

The discussion centers on calculating the concentration of H2PO4-1 at a pH of 3.21, given an initial phosphate concentration of 2.37 M and a pKa of 2.15 for H3PO4. The user initially struggles with the interpretation of "original concentration" and the application of the ICE table method. Key insights include recognizing that the concentration of H+ ions is not necessarily equal to that of H2PO4-1 at the adjusted pH, and that the total concentration of all forms of phosphoric acid must be considered. The final approach suggested involves using the relationship between the concentrations of the acid and its conjugate base without resorting to quadratic equations.

PREREQUISITES
  • Understanding of acid-base equilibria and dissociation constants.
  • Familiarity with the Henderson-Hasselbalch equation.
  • Knowledge of ICE tables for equilibrium calculations.
  • Basic proficiency in logarithmic calculations and pH concepts.
NEXT STEPS
  • Review the Henderson-Hasselbalch equation for calculating pH and concentrations of conjugate bases.
  • Learn about the dissociation constants (Ka) for polyprotic acids like phosphoric acid.
  • Study the concept of total concentration in acid-base equilibria.
  • Practice solving equilibrium problems involving multiple dissociation steps without quadratic equations.
USEFUL FOR

Chemistry students, educators, and professionals working with acid-base equilibria, particularly those studying polyprotic acids and their dissociation behavior in solution.

Shafty
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The pKa for the dissociation of H3PO4 is 2.15. What is the concentration of H2PO4-1 (in M) at pH 3.21 if the original concentration of the phosphate was 2.37 M?

My Attempt:

Key Information:

pH final: 3.21
Initial Molarity of phosphate: 2.37 M
pKa: 2.15

I started with the first dissociation of the weak acid into its proton and conjugate base.
The stoicheometry is as follows:

H3PO4 <-----> H3O+ + H2PO4-

I am only looking at the first dissociation constant K1.

pKa = -log Ka

2.15 = -log Ka = 10^-2.15 = 7.08e-3

-----This is where I am stuck------

When the question refers to the "original concentration of the phosphate", is it referring to the conjugate base or the original acid? When I try to set up an "ICE table" plugging the given molarity into the "Initial" conjugate base column, I end up with too many unknowns and can not solve quadratically. Yet when I plug the Molarity into the [HA] column I get values that do not make sense. I understand that:

Ka= [H+][A-]/[HA]

If I gloss over this middle step I can continue to find the concentration of H2PO4- ions in the final solution. Since the first dissociation is 1:1, the concentration of H+ ions will be the same as the concentration of H2PO4- ions. Therefore:

pH = 3.21 = 10^-3.21 = 6.17e-4 M

I feel like I am missing a crucial part of this problem (obviously, since my attempts have yielded wrong answers). I have solved for the original pH of the solution at 2.37 M (0.89), I just don't know how to pull all the pieces together to solve the problem. Any help would be greatly appreciated. Thank you in advance.
 
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The problem isn't very clear, unless they mean they initially started with PO_{4}^{3-} in solution. If that's the case you need a few more constants. (and it seems a little early in the semester to be working with competing equilibria, so I suspect it's not that.)

The concentration of H^{+} may not be the same as the H_{2}PO_{4}^{-} concentration if the pH was adjusted to 3.21.

I would try "initial phosphate concentration" =[H_{3}PO_{4}]+[H_{2}PO_{4}^{-}] and see what the quadratic equation gives.
 
Last edited:
As PhaseShifter suggests, treat 1M as a total concentration of all forms of pohosphoric acid.

No need for quadratic though. Take a look here:

acid base titration indicators

Don't pay attention to the fact it describes indicator, formula derived works for ANY acid.

--
 

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