Conceptual Question: Vector-Matrix Differential Equation

Click For Summary
SUMMARY

The discussion centers on solving the vector-matrix differential equation represented as dy/dt = A(t)y, where y is a vector and A(t) is an nxn matrix. The solution is expressed as y = ce^(A(t)), with the Taylor series expansion providing a method to compute y(t) using the formula y(t) = e^(A(t))y0 = Σ (1/k!)A(t)^k y0. Participants emphasize the importance of truncating the series based on a predetermined error tolerance to achieve accurate results for specific components of the vector at time t.

PREREQUISITES
  • Understanding of differential equations, particularly vector-matrix forms.
  • Familiarity with matrix exponentiation and its applications.
  • Knowledge of Taylor series and its convergence criteria.
  • Basic linear algebra concepts, including vector and matrix operations.
NEXT STEPS
  • Study matrix exponentiation techniques in detail.
  • Explore Taylor series applications in solving differential equations.
  • Learn about numerical methods for approximating solutions to differential equations.
  • Investigate error analysis in numerical computations for differential equations.
USEFUL FOR

Mathematicians, engineers, and students studying differential equations, particularly those working with vector-matrix systems and seeking to improve their understanding of numerical solutions and error management.

adamjts
Messages
24
Reaction score
0
Hi I'm just having trouble wrapping my head around differential equations with matrices and vectors...
For example:

let y be a vector.
let A(t) be an nxn matrix.

I have the differential equation:
dy/dt = A(t)y

So I think I understand why the solution is

y = ceA(t)

But I'm having trouble understanding how to actually get information from this. For example, if someone asked be to find the yi component at some time t, I wouldn't know how to do it. My friend told me to think of the as a taylor expansion, but I'm still not entirely understanding how to do this. Can someone help explain?
 
Physics news on Phys.org
The Taylor series is
$$\vec y(t)= e^{A(t)}\vec y_0=\sum_{k=0}^\infty \frac{1}{k!}A(t)^k\vec y_0$$
You include only the elements of the infinite sum up to the point at which all components of the most recently added element are smaller than the tolerable error you have decided upon.
So, with that number of elements, the sum is simply a finite sum of vectors, each of which is a finite power of a known matrix ##A(t)##, applied to the known vector ##\vec y_0##.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 0 ·
Replies
0
Views
4K