1. Dec 10, 2014 #1

   torquerotates

   

   So I'm trying to find E(X1,X2|Xn) where X1,X2,.....Xn are the numbers of cell observations in a multinomial distribution.
   
   
   How do I even calculate this? I know it is not independent so I cannot split it.
   
   Does it have something to do with the fact that E(Xi)=nPi ?

    

   torquerotates, Dec 10, 2014
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3. Dec 10, 2014 #2

   Stephen Tashi

   

   Science Advisor

   Intuitively, we would expect the distribution of [itex](X1, X2| Xn = 6) [/itex] to be a multinomial distribution for 6 less objects with the cell probabilities for [itex] X1, X2,..X[n-1] [/itex] scaled by a factor so they sum to 1. I don't know what your notation [itex] E(X1,X2...[/itex] means. Are you asking about a vector of expectations?

    

   Stephen Tashi, Dec 10, 2014
4. Dec 11, 2014 #3

   torquerotates

   

   Interesting. Makes sense.
   
   Well, E(X1,X2) is just expectation of x1 and x2

    

   torquerotates, Dec 11, 2014

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