Conditional expectation, Lebesgue measure

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Homework Statement



Let Ω = [0,1] with the σ-field of Borel sets and let P be the Lebesgue measure on [0,1]. Find E(X|Y) if:

Homework Equations



[itex]X(w)=5w^2[/itex]

[itex]Y(w)= \left\{ \begin{array}{ll}<br /> 4 & \mbox{if $w \in [0,\frac{1}{4}]$} \\<br /> 2 & \mbox{if $w \in (\frac{1}{4},1]$} \\<br /> \end{array}<br /> \right.[/itex]

The Attempt at a Solution



For [itex]w\in A_1=[0,\frac{1}{4}][/itex]:

[itex]E(X|Y)(w)=E(X|A_1)=\frac{\int_{A_1}x\,dp}{P(A_1)}=\frac{1}{{P(A_1)}} \displaystyle\int_{0}^{1/4}5w^2\,dw[/itex]

Do I use [itex]P(A_1)=P(A_2)=\frac{1}{2}[/itex],

or [itex]P(A_1)=\frac{1}{4}[/itex], and [itex]P(A_2)=\frac{3}{4}[/itex] ?
 
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spitz said:

Homework Statement



Let Ω = [0,1] with the σ-field of Borel sets and let P be the Lebesgue measure on [0,1]. Find E(X|Y) if:

Homework Equations



[itex]X(w)=5w^2[/itex]

[itex]Y(w)= \left\{ \begin{array}{ll}<br /> 4 & \mbox{if $w \in [0,\frac{1}{4}]$} \\<br /> 2 & \mbox{if $w \in (\frac{1}{4},1]$} \\<br /> \end{array}<br /> \right.[/itex]

The Attempt at a Solution



For [itex]w\in A_1=[0,\frac{1}{4}][/itex]:

[itex]E(X|Y)(w)=E(X|A_1)=\frac{\int_{A_1}x\,dp}{P(A_1)}=\frac{1}{{P(A_1)}} \displaystyle\int_{0}^{1/4}5w^2\,dw[/itex]

Do I use [itex]P(A_1)=P(A_2)=\frac{1}{2}[/itex],

or [itex]P(A_1)=\frac{1}{4}[/itex], and [itex]P(A_2)=\frac{3}{4}[/itex] ?

You said that P was Lebesgue measure, so what do you think is the Lebesgue measure of [0,1/4]?

RGV