Conduction what if questions

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The Biot number (hL/k) is crucial in determining the validity of the lumped capacitance method for transient conduction problems. When the Biot number is greater than 0.1, it indicates that there are significant temperature gradients within the solid, contradicting the lumped capacitance assumption of uniform temperature. In such cases, the solid will exhibit a non-uniform temperature distribution, leading to longer times to reach steady state than predicted. The discussion highlights that a Biot number much less than 1 suggests negligible internal temperature gradients compared to those in the fluid boundary layer. Therefore, accurate analysis requires careful consideration of the Biot number to avoid underestimating transient response times.
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Conduction "what if" questions...

What is the Biot number (hL/k) is greater than 0.1 and I use the lumped capacitance method for analysis (i.e. there are temperature gradients in the "lump" and I have assumed they are absent). What effect does it have on the result?

What is the largest number of non-homogeneities that can exist in a conduction solution?
 
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The Biot number is used to determine if the lumped capacitance method is a valid approximation of a transient problem that involves convection about a solid. When the Biot number is much less than 1, the resistance to conductive heat transfer within the solid is much less than the resistance to convective heat transfer across the fluid boundary layer.

Put another way, if the Biot number is much less than 1 then the temperature gradient across the solid is much less than the temperature gradient across the fluid boundary layer. Given two temperature gradients, if one is much larger than the other then the smaller one can be assumed to have a negligeble effect on the system, and so it may be disregarded.

To answer your question, if you use the lumped capacitance method for a system where the biot number is close to or higher than one, the solid your are analyzing will have a non-uniform temperature distribution in it. So if this is the case, the system will take longer to reach steady state than your calculation implies.
 
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