Confused About Exercise 11 Answer Key

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SUMMARY

The discussion centers around the confusion regarding Exercise 11's answer key, specifically the status of vectors b and w in relation to the column space of matrix A. User $$|\pi\rangle$$ initially states that b is not in col(A) while the answer key claims otherwise. After further analysis and corrections to their matrix, $$|\pi\rangle$$ concludes that b is indeed in col(A). The conversation also touches on the importance of understanding the reasoning behind answers rather than relying solely on answer keys, which can sometimes be incorrect.

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Petrus
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Hello,

in exercise 11, I get b is not and w is, but the answer key says b is and w is not...? I don't understand...have I misunderstood or is the answer key wrong?

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Regrds,
$$|\pi\rangle$$
 

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I don't know who/what facit is, but he/she/it is correct. Perhaps if you post your solution, we can discuss it.
 
Petrus, I suggest if you are going to upload images that you use some sort of image editing software to rotate the image so that it is the right side up for ease of reading. :D
 
Evgeny.Makarov said:
I don't know who/what facit is, but he/she/it is correct. Perhaps if you post your solution, we can discuss it.

Somehow he is referring by facit to the textbook.
 
MarkFL said:
Petrus, I suggest if you are going to upload images that you use some sort of image editing software to rotate the image so that it is the right side up for ease of reading. :D
What do you mean by rotate? The picture seem nice to me
2zog2u1.jpg
 
Yes, the facit refers to the answer key (I have edited the post), and I have rotated, cropped, re-sized and uploaded the new image. (Sun)

edit: Petrus, on my computer, the image needed to be rotated clockwise 90 degrees.
 
Evgeny.Makarov said:
I don't know who/what facit is, but he/she/it is correct. Perhaps if you post your solution, we can discuss it.
If we start with col(a)

after row reduce we got 1 0 -1|3
----------------------------0 1 2|-1
that means we got infinity soloution, if we set $$x_3=t$$ we got $$x_2=-1-2t$$ and $$x_1= 3+t$$ it indeed got soloution so it is in col(A)
Right?

Regards,
$$|\pi\rangle$$

- - - Updated - - -

MarkFL said:
Yes, the facit refers to the answer key (I have edited the post), and I have rotated, cropped, re-sized and uploaded the new image. (Sun)

edit: Petrus, on my computer, the image needed to be rotated clockwise 90 degrees.
Strange and thanks for doing that! I did not know it needed to be rotated cause it showed correctly for me:S That is strange
 
Petrus said:
in exercise 11, I get b is not and w is, but the answer key says b is and w is not...?
Petrus said:
If we start with col(a)

after row reduce we got 1 0 -1|3
----------------------------0 1 2|-1
that means we got infinity soloution, if we set $$x_3=t$$ we got $$x_2=-1-2t$$ and $$x_1= 3+t$$ it indeed got soloution so it is in col(A)
Right?
Yes, but in post #1 you said that $b$ is not in $\text{col}(A)$.
 
Evgeny.Makarov said:
Yes, but in post #1 you said that $b$ is not in $\text{col}(A)$.
That'S cause I got actually wrong number in My matrice somehow.. Sorry My bad and now I correctly Solved it:)
Regards,
$$|\pi\rangle$$
 
Last edited:
  • #10
(3,2) = 3(1,1) + (-1)(0,1). This proves b is in col(A).

******

On the other question if a(1,0,-1) + b(1,1,1) = (a+b,b,b-a) = (-1,1,1), we must have

b = 1, leading to:

a+1 = -1 --> a = -2
1-a = 1 --> a = 0.

Since -2 is not 0 (unless you are in a field of characteristic two, and then there is no "3"), this is impossible.

******

Answer keys are evil...let me explain why: the point of learning math is not to get "answers" but rather, to be confident the answers you obtain are correct. Not only doesn't the "real world" come with an answer key, but one has only logical reasoning as a test of one's sanity. If one's only experience with riding a bike is with training wheels, one does not know how to ride a bike. Also, answer keys can be erroneous, and proof by authority is not a valid mathematical method.
 

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