Confused in stat. mech.-thermo., inconsistant result

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SUMMARY

The discussion centers on calculating the internal energy and specific heat of a diatomic ideal gas consisting of N distinct molecules at high temperatures. The participant initially derived the Helmholtz free energy, resulting in an incorrect expression for internal energy, U, which was not extensive. The error was identified as a failure to multiply the Helmholtz free energy by beta before differentiation. The correct approach leads to the mean energy per molecule aligning with the expected solution.

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  • Knowledge of thermodynamic variables such as temperature (T) and beta (β).
  • Ability to differentiate functions with respect to thermodynamic variables.
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Homework Statement


Hello guys,
Long problem but I'll drastically shorten it. I've a diatomic ideal gas of N molecules (the 2 atoms are distinct). I must calculate the internal energy and the specific heat for high temperatures.
I've got the solution but if I solve it my way in the last step, I get a different result.

Homework Equations


Partition function of one molecule: ##Z_1\approx \frac{T}{\omicron}##. This expression is to be found in the solution for this exercise.
Thus, for N molecules, i.e. the whole system: ##Z_N\approx \left ( \frac{T}{\omicron} \right ) ^N## (according to me). These approximations are valid for ##T>>\omicron##.
The solution states that from ##Z_1##, we can calculate the mean energy per molecule as ##\overline{\varepsilon}=-\frac{\partial Z_1 }{\partial \beta}=kT##.

The Attempt at a Solution


My idea was to get the Helmholz free energy and then, from it, getting the internal energy.
I got ##A(\beta,N) \approx -\frac{N}{\beta} \ln \left ( \frac{1}{k\beta \omicron} \right )##.
Since ##U=\left ( \frac{\partial A}{\partial \beta} \right ) _{V,N}##, I got ##U \approx\frac{N}{\beta ^2}[1-\ln (k\beta \omicron)]##. As you can see:
1)My result for U is not extensive (so I'm fried).
2)Dividing my expression for U by N, I don't reach the expression for the average energy per molecule the solution provides.

I don't understand what I did wrong.
 
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Nevermind guys, I found out the mistake. I had to multiply A by beta before taking the derivative with respect to beta, in order to get the internal energy.
 

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