Confused on statistical mechanics problem

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The discussion revolves around calculating the total partition function for a dilute gas of non-interacting atoms with two intrinsic energy states. Participants express confusion about whether to use a discrete sum or a continuous integral approach, particularly in relation to incorporating the volume of the system into the partition function. There is debate over the necessity of delta functions for discrete energy levels and whether the volume should be included in the calculation. Some contributors suggest that the volume might not be essential for the problem, while others emphasize its importance in the context of the partition function. Overall, the thread highlights a common uncertainty in applying statistical mechanics principles to specific problems.
TroyElliott
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Homework Statement


A dilute gas of N non-interacting atoms of mass m is contained in a volume V and in equilibrium with the surroundings at a temperature T. Each atom has two (active) intrinsic states of energies ε = 0 and ∆, respectively. Find the total partition function of the gas.

Homework Equations


Partition function.

The Attempt at a Solution


For discrete energy levels we normally write ##Z = \sum_{i}e^{-\beta \epsilon_{i}},## and the volume of the system appears in the energy spectrum e.g. particle in a box energy spectrum. For a classical system we write $$Z=\frac{1}{h^{3}}\int e^{H(q,p)}d^{3}qd^{3}p.$$ We can write

$$Z = \frac{V}{h^{3}}\int e^{-\beta p^{2}/2m}d^{3}p,$$
##\frac{p^{2}}{2m} = \epsilon## implies ##d\epsilon = \frac{p}{m}dp = \frac{\sqrt{2m\epsilon}}{m}dp## which means we can write ##dp = \sqrt{\frac{m}{2\epsilon}}d\epsilon## and the partition function becomes

$$Z = (\frac{m}{2})^{3/2}\frac{V}{h^{3}}\int e^{-\epsilon}\epsilon^{-3/2}d^{3}\epsilon.$$

Should I be including delta functions in order to pick off the two discrete energy levels? or is there an easier way in going about this problem?

Thank you!
 
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You said yourself; “for discrete energy levels we use the discrete sum over energy levels,” but then you use the continuous energy formulation??

Finding a discrete sum by integrating over Dirac-delta spikes seems pretty silly!(Sorry if I’m missing something; I’m also learning the subject.)
 
I am just confused on how to incorporate the volume ##V## into the picture by evaluating ##Z = \sum_{i} e^{-\beta \epsilon_{i}} = (1+e^{-\beta \Delta})^{N}.## Maybe it is as simple as multiplying this by ##\frac{V}{h^{3}}.##
 
Just because they give the volume V doesn’t mean we have to use it!

I don’t know quantum mechanics, but I would think V would appear inside Δ. But since some authority tells us what Δ is, then I don’t think we need to use V.

Anyway I’ll shut up now. Let’s wait for someone who actually knows what they’re talking about to chime in! o0)
 

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