Confused on statistical mechanics problem

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Homework Help Overview

The discussion revolves around a statistical mechanics problem involving a dilute gas of non-interacting atoms with two intrinsic energy states. The original poster seeks to find the total partition function of the gas while considering the implications of volume in the calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the appropriate formulation for the partition function, with some suggesting the use of discrete sums for energy levels while others question the integration approach. There is also uncertainty about how to incorporate the volume into the partition function.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of how to approach the problem. Some guidance has been offered regarding the use of discrete versus continuous formulations, but no consensus has been reached on the best method to incorporate volume.

Contextual Notes

There is a mention of the original poster's confusion regarding the role of volume in the partition function, as well as differing levels of familiarity with quantum mechanics among participants. The discussion reflects a mix of assumptions about the problem setup and the relevance of given parameters.

TroyElliott
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Homework Statement


A dilute gas of N non-interacting atoms of mass m is contained in a volume V and in equilibrium with the surroundings at a temperature T. Each atom has two (active) intrinsic states of energies ε = 0 and ∆, respectively. Find the total partition function of the gas.

Homework Equations


Partition function.

The Attempt at a Solution


For discrete energy levels we normally write ##Z = \sum_{i}e^{-\beta \epsilon_{i}},## and the volume of the system appears in the energy spectrum e.g. particle in a box energy spectrum. For a classical system we write $$Z=\frac{1}{h^{3}}\int e^{H(q,p)}d^{3}qd^{3}p.$$ We can write

$$Z = \frac{V}{h^{3}}\int e^{-\beta p^{2}/2m}d^{3}p,$$
##\frac{p^{2}}{2m} = \epsilon## implies ##d\epsilon = \frac{p}{m}dp = \frac{\sqrt{2m\epsilon}}{m}dp## which means we can write ##dp = \sqrt{\frac{m}{2\epsilon}}d\epsilon## and the partition function becomes

$$Z = (\frac{m}{2})^{3/2}\frac{V}{h^{3}}\int e^{-\epsilon}\epsilon^{-3/2}d^{3}\epsilon.$$

Should I be including delta functions in order to pick off the two discrete energy levels? or is there an easier way in going about this problem?

Thank you!
 
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You said yourself; “for discrete energy levels we use the discrete sum over energy levels,” but then you use the continuous energy formulation??

Finding a discrete sum by integrating over Dirac-delta spikes seems pretty silly!(Sorry if I’m missing something; I’m also learning the subject.)
 
I am just confused on how to incorporate the volume ##V## into the picture by evaluating ##Z = \sum_{i} e^{-\beta \epsilon_{i}} = (1+e^{-\beta \Delta})^{N}.## Maybe it is as simple as multiplying this by ##\frac{V}{h^{3}}.##
 
Just because they give the volume V doesn’t mean we have to use it!

I don’t know quantum mechanics, but I would think V would appear inside Δ. But since some authority tells us what Δ is, then I don’t think we need to use V.

Anyway I’ll shut up now. Let’s wait for someone who actually knows what they’re talking about to chime in! o0)
 

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