Confusing Limit Problem: Solving lim[x→-2¯(from the left)] x+2/sqrt(x^2-4)

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Homework Help Overview

The discussion revolves around evaluating the limit as x approaches -2 from the left for the expression (x + 2) / sqrt(x^2 - 4). Participants express confusion regarding the behavior of the limit and whether it is defined or approaches a specific value.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the potential for the limit to be undefined versus approaching zero, with references to graphical interpretations and the use of L'Hôpital's rule. Some express skepticism about the applicability of L'Hôpital's rule in this case.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and questioning the validity of different approaches. There is no clear consensus, as differing opinions on the limit's value are presented.

Contextual Notes

Some participants mention the use of calculators and graphical methods, while others highlight the challenges posed by the expression's behavior near the limit point.

collinito
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Homework Statement


lim[x→-2¯(from the left)] x+2/sqrt(x^2-4)

Homework Equations


The Attempt at a Solution


When I attempted this question I felt that the solution was that this is undefined and when i put it into my ti-89 it said that too. My friend argues that it's actually zero as that's what the leftbound limit approaches graphically. I am curious now to know the answer to this one
 
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collinito said:

Homework Statement


lim[x→-2¯(from the left)] x+2/sqrt(x^2-4)


Homework Equations





The Attempt at a Solution


When I attempted this question I felt that the solution was that this is undefined and when i put it into my ti-89 it said that too. My friend argues that it's actually zero as that's what the leftbound limit approaches graphically. I am curious now to know the answer to this one

Welcome to the PF. Can you use this:

http://en.wikipedia.org/wiki/L'hospital's_rule

.
 
l'hospital's doesn't work, I already tried it, you still get a zero on the bottom.
 
collinito said:
l'hospital's doesn't work, I already tried it, you still get a zero on the bottom.

Maybe you do, but I don't. Can you show us your work using L'Hopital's rule?
 
x^2-4 = (x-2)(x+2)
 

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