Confusion about linear equations

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SUMMARY

A linear equation is defined as a polynomial of first degree, while a linear differential equation, such as 5.dy(x)/dx = x.y(x), represents a different concept. The confusion arises from the distinction between linear equations in algebra and linear differential equations, where the latter involves operators acting on functions. The operator D, which denotes differentiation, leads to the formulation (D-Q)f=0, confirming the linearity of the differential equation. In contrast, the function f(x,y)=axy+b is classified as a polynomial of second degree and is not linear.

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Students and professionals in mathematics, physics, and engineering who seek clarity on the distinctions between linear equations and linear differential equations.

bentley4
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Hi everyone!

1. Is a linear equation the same as a polynomial of first(or 0th) degree?
2. The book 'Mathematics for physicists and engineers' by springer(publisher) states that an example of a linear (DE) equation is 5.dy(x)/dx = x.y(x). Yet I read somewhere else that f(x,y)=a.x.y+b is not linear.(polynomial of 2nd degree).
Is one them wrong? Or are both right because in the first example y is a depent variable while in the second example y is an independent variable?
 
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I think you have a language mix up here. The first equation is a linear differential equation, which means something different than linear equation in the basic algebraic sense.
 
If you denote the operator that takes a differentiable function f to its derivative f' by D, then your differential equation can be written as Df(x)=xf(x), or equivalently, as (D-Q)f=0, where I have defined a new operator Q by Qf(x)=xf(x). The equation (D-Q)f=0 is said to be linear because the operator D-Q is linear.

The function f defined by f(x,y)=axy+b is clearly not linear.


(Recall that a function T from a vector space to a vector space is said to be linear if T(ax+by)=aTx+bTy for all scalars a,b and all vectors x,y).
 

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