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My question is how can the Z factor be irrelevant for calculations at the leading order of perturbation theory. Thanks.

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My question is how can the Z factor be irrelevant for calculations at the leading order of perturbation theory. Thanks.

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Z is the field-strength renormalization factor

My question is how can the Z factor be irrelevant for calculations at the leading order of perturbation theory. Thanks.

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DarMM

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At the lowest order in perturbation theory it is just ##1##.

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@DarMM thank you. Now I got it, for electron, $Z_2^(-1)=1-\frac{d\Sigma}{d\slashed{p}}|_{\slashed{p}=m}$, at the leading-order contribution, electron self-energy is 0, so Z=1.At the lowest order in perturbation theory it is just ##1##.

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DarMM

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