Conservation of Angular Momentum sun problem

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SUMMARY

The discussion centers on the conservation of angular momentum in the context of a star like the Sun collapsing into a white dwarf. The initial parameters include the Sun's mass and radius (6.96×108 m) with a rotation period of 25 days, transitioning to a white dwarf with 53% of the Sun's mass and a rotation period of 131 seconds. The conservation of angular momentum equation is applied, leading to the calculation of the white dwarf's radius, which was initially found to be incorrect. The correct approach involves considering only the inner 53% of the star's mass when applying the conservation principle.

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  • Understanding of conservation of angular momentum
  • Familiarity with rotational inertia calculations for spheres
  • Knowledge of angular velocity and its calculation
  • Basic astrophysics concepts regarding stellar evolution
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  • Learn about the properties of white dwarfs and their formation processes
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  • Investigate the effects of mass loss during stellar evolution on angular momentum
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Godcanthelp
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Homework Statement


When a star like our Sun exhausts its fuel, thermonuclear reactions in its core cease, and it collapses to become a white dwarf. Often the star will blow off its outer layers and lose some mass before it collapses. Suppose a star with the Sun’s mass and radius (the radius of the Sun is 6.96×108m ) is rotating with period 25 days and then it collapses to a white dwarf with 53% of the Sun’s mass and a rotation period of 131 s.


Homework Equations


Conservation of Angular Momentum:
Angular Momentuminitial = Angular Momentum final
Angular Momentum = Rotational Inertia (sphere) * Angular Velocity (ω)
Rotational Inertia (sphere) = 2/5MR2

The Attempt at a Solution



ωsun = 2∏/(25*24*60*60) rad/sec
ωwd = 2∏/131 rad/sec

Isunsun = Iwdwd
(2/5)*Msun*Rsun2*2∏/(25*24*60*60) = (2/5)*Mwd*Rwd2*2∏/131

Msun*(6.96*108)2*1/(25*24*60*60) = 0.53*Msun*Rwd2*1/131

(6.96*108)2*1/(25*24*60*60) = 0.53*Rwd2*1/131

Rwd2 = 131*(6.96*108)2*1/(25*24*60*60) *1/0.53

Rwd = 7.44526*106m

Which is incorrect.
 
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Godcanthelp said:

Homework Statement


When a star like our Sun exhausts its fuel, thermonuclear reactions in its core cease, and it collapses to become a white dwarf. Often the star will blow off its outer layers and lose some mass before it collapses. Suppose a star with the Sun’s mass and radius (the radius of the Sun is 6.96×108m ) is rotating with period 25 days and then it collapses to a white dwarf with 53% of the Sun’s mass and a rotation period of 131 s.

Homework Equations


Conservation of Angular Momentum:
Angular Momentuminitial = Angular Momentum final
Angular Momentum = Rotational Inertia (sphere) * Angular Velocity (ω)
Rotational Inertia (sphere) = 2/5MR2

The Attempt at a Solution



ωsun = 2∏/(25*24*60*60) rad/sec
ωwd = 2∏/131 rad/sec

Isunsun = Iwdwd
(2/5)*Msun*Rsun2*2∏/(25*24*60*60) = (2/5)*Mwd*Rwd2*2∏/131

Msun*(6.96*108)2*1/(25*24*60*60) = 0.53*Msun*Rwd2*1/131

(6.96*108)2*1/(25*24*60*60) = 0.53*Rwd2*1/131

Rwd2 = 131*(6.96*108)2*1/(25*24*60*60) *1/0.53

Rwd = 7.44526*106m

Which is incorrect.

You seem to have left out the the primary goal in the problem statement. Are you supposed to find the white dwarf's radius?

The approach you are using makes a few approximations, such as the original star having a uniform density. And crazy as it sounds, it's difficult to gauge a real star's rotation rate since it rotates at a different angular speed at its equator than it does at it's poles (I know, weird huh).

But let's just approximate it as a rotating, solid sphere with uniform density anyway.

Only 53% of the original star's mass ends up collapsing into a white dwarf. The rest gets blown off.

My guess is you should not start with the angular momentum of the entire star. Instead, only consider the inner 53% of that star. So first, find the radius of the inner 53% by mass of that star. Then apply conservation of angular momentum after that.
 
Last edited:

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