PeterDonis
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Doing this requires considering the system you are measuring as an open system--it exchanges energy with other systems, during measurement, and also, as you point out, during preparation. So you would not expect the energy of the system alone to be conserved at all; it's an open system. To evaluate conservation of energy at all, you would need to include other systems as well. (And you still have the issue @Nugatory raised in post #31 to deal with.)pines-demon said:You put some energy to prepare the state, then you measure some energy (plus the energy you gain-lose in order to perform the measurement).
But the point is that the paper referenced in the OP does not do any of that. It only looks at the system being measured (and as far as I can tell, it does not look at the preparation process at all). So any evaluation it makes of conservation of energy can't possibly be correct.