Well... It is first first time on the Physics Forums, and I'm stuck on this problem: 1. A 2.5 kg block of ice at a temperature of 0.0 °C and an initial speed of 5.7 m/s slides across a level floor. if 3.3 × 10^5 J are required to melt 1.0 kg of ice, how much ice melts, assuming that the initial kinetic energy of the ice block is entirely converted to the ice's internal energy? 2. ∆PE + ∆KE +∆U = 0 (the change in potential energy + the change in kinetic energy + the change in internal energy = 0) PE = mgh KE = ½mv² 3. Well... I really have no idea how to solve this one... But it sounds to me that KE = ½(2.5 kg)(5.7 m/s)² somewhere in there... But I really don't know what I am supposed to solve for (I think it is the mass of how much ice melts). I don't know how to integrate 3.3 × 10^5 J into an equation. If I could get a equation to start off from, I could do the rest. Thanks.