- #1

Lunar Guy

- 17

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Well... It is first first time on the Physics Forums, and I'm stuck on this problem:

**1. A 2.5 kg block of ice at a temperature of 0.0 °C and an initial speed of 5.7 m/s slides across a level floor. if 3.3 × 10^5 J are required to melt 1.0 kg of ice, how much ice melts, assuming that the initial kinetic energy of the ice block is entirely converted to the ice's internal energy?****2. ∆PE + ∆KE +∆U = 0**

(the change in potential energy + the change in kinetic energy + the change in internal energy = 0)

PE = mgh

KE = ½mv²(the change in potential energy + the change in kinetic energy + the change in internal energy = 0)

PE = mgh

KE = ½mv²

**3. Well... I really have no idea how to solve this one...**

But it sounds to me that KE = ½(2.5 kg)(5.7 m/s)² somewhere in there... But I really don't know what I am supposed to solve for (I think it is the mass of how much ice melts). I don't know how to integrate 3.3 × 10^5 J into an equation. If I could get a equation to start off from, I could do the rest. Thanks.But it sounds to me that KE = ½(2.5 kg)(5.7 m/s)² somewhere in there... But I really don't know what I am supposed to solve for (I think it is the mass of how much ice melts). I don't know how to integrate 3.3 × 10^5 J into an equation. If I could get a equation to start off from, I could do the rest. Thanks.

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