A particle of mass 5m moving with speed v explodes and spilts into two pieces with masses of 2m and 3m. The lighter piece continues to move in the original direction with speed 5v relative to the heavier piece. what is the actual speed of the lighter piece?
using law of conservation of linear momentum
initial moment = final moment
mass (m) x Velocity (v) = mass (m) x Velocity (v)
The Attempt at a Solution
using the formula...
5m (v) = 2m(v) - 3m (5v) ....) i used the minus (-) sign because the heavier piece went a different direction
5mv = 2mv -15mv
20mv = 2mv
10v = v
but my answer was wrong....
PLEASE HELP EXPLAIN WHY AND WHAT IS IT IM MISSING TO DO>>>
FIRST CLASS TEST IS TOMORROW!