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## Homework Statement

A projectile with a mass of 20 g has an initial horizontal velocity of 100 m/s when it hits and stops in a wood block of mass 0.402 kg. The block is sitting on a horizontal frictionless surface and is attached to a massless spring, initially relaxed, with spring constant 143 N/m. What is the maximum compression of the spring?

## Homework Equations

P= MV

K=1/2 MV^2

F=-kx

## The Attempt at a Solution

Initial Momentum of the Bullet = .02 x 100 = 2

Initial momentum of the Bullet/Wood system = 2 due to conservation of momentum.

2= .404 V

V= 4.95 m/s is the velocity of the block/bullet system.

K = 1/2 (.404) 4.95^2

K= 4.95 Due to conservation of Energy, this is also the amount of energy the spring exerts.

4.95 =143X

Wrong. I suspect the error in my calculation is near the end, but I don't know that for certain.