An 82-kg lumberjack stands at one end of a 380-kg floating log, as shown in the figure (Figure 1) . Both the log and the lumberjack are at rest initially.
If the lumberjack now trots toward the other end of the log with a speed of 2.7 m/s relative to the log, what is the lumberjack's speed relative to the shore? Ignore friction between the log and the water.
Express your answer using two significant figures.
Conservation of Momentum
The Attempt at a Solution
m1v1' + m2v2' = 0
m1v1' = -m2v2'
(82)(2.7) = (-380)(v2')
v2' = -0.5826
velocity in respect to shore = 2.7 + (-0.5826) = 2.1 m/s
For some reason this answer is incorrect. I also tried 2.7 + 0.5826 = 3.3 m/s, but that is wrong also. Is there something that I am doing incorrectly before this last step?