- #1

Erenjaeger

- 141

- 6

## Homework Statement

A lumberjack (mass = 111 kg) is standing at rest on one end of a floating log (mass = 259 kg) that is also at rest. The lumberjack runs to the other end of the log, attaining a velocity of +2.93 m/s relative to the shore, and then hops onto an identical floating log that is initially at rest. Neglect any friction and resistance between the logs and the water. (a) What is the velocity of the first log (again relative to the shore) just before the lumberjack jumps off? (b) Determine the velocity of the second log (again relative to the shore) if the lumberjack comes to rest relative to the second log.

(not sure if the title is fitting, because not 100% this is actually a momentum question)[/B]

## Homework Equations

p=mv[/B]

## The Attempt at a Solution

so i found the momentum of the lumerjack by mv which was 111x2.93=325.23 kg m/s which has to equal the momentum of the log and we know the mass of the log is greater than that of the lumberjack it is 259kg so obviously for the momentum to be conserved the velocity has to be a lot slower. so i went 325.23kg m/s = 259kg⋅Vm/s and solved for velocity by dividing 325.23 by 259 which was 1.256 but the velocity as a vector is going to be in the other direction so the answer is -1.256m/s.

Im struggling on finding the velocity of the second log after the lumberjack jumps on it relative to the shore. [/B]