Conservation of momentum and SHM

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  • #1
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Homework Statement


Two point masses m1 and m2 are coupled by a spring of spring constant k and uncompressed length L0. The spring is fully compressed and a thread ties the masses together with negligible separation between them. The tied assembly is moving in the +x direction with uniform speed v0. At a time, say t = 0, it is passing the origin and at that instant the thread breaks. The masses, attached to the spring, start oscillating. The displacement of mass m1 is given by x1 (t) = v0t - A(1-cos(ωt)) where A is a constant. Find (i) the displacement x2(t) of mass m2, and (ii) the relationship between A and L0.

Homework Equations




The Attempt at a Solution


First part is easy. Using
##x_{cm} = \dfrac{m_1x_1 + m_2x_2}{m_1 + m_2}##
and substituting ##x_{cm} = v_0t## and ##x_1= v_0t - A(1-\cos{ωt})##
we get ##x_2 = v_0t + \dfrac{m_1}{m_2}.A(1-\cos{wt})##

However, I'm not sure what to do for part (ii). I suppose it involves using the energy equation, but that isn't really working out because of the ##t## (time). I think we might have to minimise or maximise something, in any case, I'm not sure how to proceed. Please help.
 

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  • #2
haruspex
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Homework Statement


Two point masses m1 and m2 are coupled by a spring of spring constant k and uncompressed length L0. The spring is fully compressed and a thread ties the masses together with negligible separation between them. The tied assembly is moving in the +x direction with uniform speed v0. At a time, say t = 0, it is passing the origin and at that instant the thread breaks. The masses, attached to the spring, start oscillating. The displacement of mass m1 is given by x1 (t) = v0t - A(1-cos(ωt)) where A is a constant. Find (i) the displacement x2(t) of mass m2, and (ii) the relationship between A and L0.

Homework Equations




The Attempt at a Solution


First part is easy. Using
##x_{cm} = \dfrac{m_1x_1 + m_2x_2}{m_1 + m_2}##
and substituting ##x_{cm} = v_0t## and ##x_1= v_0t - A(1-\cos{ωt})##
we get ##x_2 = v_0t + \dfrac{m_1}{m_2}.A(1-\cos{wt})##

However, I'm not sure what to do for part (ii). I suppose it involves using the energy equation, but that isn't really working out because of the ##t## (time). I think we might have to minimise or maximise something, in any case, I'm not sure how to proceed. Please help.
Energy should do it. Please post your working.
 
  • #3
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Sorry. I forgot to post the working.
Conserving energy at t=0 and t=t,

##\dfrac{1}{2}.k{L_0}^2 + \dfrac{1}{2}(m_1 + m_2){v_0}^2 = \dfrac{1}{2}k{(L_0 - |x_2 - x_1|)}^2 + \dfrac{1}{2}m_1{v_1}^2 + \dfrac{1}{2}m_2{v_2}^2##

where ##v_1 = v_0 - Aω\sin{ωt}## and ##v_2 = v_0 + A\dfrac{m_1}{m_2}ω\sin{ωt}##

This is just terrible.
So, I'm thinking there is definitely some optimisation involved, something like ##\sin{ωt} = 0## or ## \cos{ωt} = 0## but I'm not seeing what.
 
  • #4
haruspex
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Sorry. I forgot to post the working.
Conserving energy at t=0 and t=t,

##\dfrac{1}{2}.k{L_0}^2 + \dfrac{1}{2}(m_1 + m_2){v_0}^2 = \dfrac{1}{2}k{(L_0 - |x_2 - x_1|)}^2 + \dfrac{1}{2}m_1{v_1}^2 + \dfrac{1}{2}m_2{v_2}^2##

where ##v_1 = v_0 - Aω\sin{ωt}## and ##v_2 = v_0 + A\dfrac{m_1}{m_2}ω\sin{ωt}##

This is just terrible.
So, I'm thinking there is definitely some optimisation involved, something like ##\sin{ωt} = 0## or ## \cos{ωt} = 0## but I'm not seeing what.
It is not a question of optimisation. You need to pick a particular time t to compare with t=0.
 
  • #5
(ii) maximum compression = maximum stretching = L
So max. gap btw. x1 and x2 = max. Stretch + natural length = L + L = 2L
x2 - x1 = Am1/m2(1-coswt) + A(1-coswt)
(x2 - x1) max. =» 2A(m1/m2) + 2A = 2L
L = A(m1 + m2)/m2
 
  • #6
PeroK
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(ii) maximum compression = maximum stretching = L
So max. gap btw. x1 and x2 = max. Stretch + natural length = L + L = 2L
x2 - x1 = Am1/m2(1-coswt) + A(1-coswt)
(x2 - x1) max. =» 2A(m1/m2) + 2A = 2L
L = A(m1 + m2)/m2
The original post was from 3 years ago!
 

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