Momentum conservation in collisions and swimmer diving off boat

[wakejosh]

two questions actually:

1. In a system with two moving objects, when a collision occurs
between the two objects,
what is conserved?

a. the total kinetic energy is always conserved
b. the total momentum is always conserved
c. the total kinetic energy and total momentum are always conserved
d. neither the kinetic energy nor the momentum is conserved
e. the total momentum is never conserved

-from what I understand B is the right answer, and If the collision was elastic C would be true, but in this case I think B is the right answer because I know in an isolated collision momentum is always conserved.


with this next question I am having trouble finding the equation I need if anyone can point me in the right direction.

2. A 50 kg swimmer dives horizontally off a 75 kg rowboat. If the
speed of the rowboat
immediately after the swimmer dives off is 1.0 m/s, what speed did
the diver leave the
rowboat?

 

[wakejosh]

any feedback?

ive been trying to figure out the 2nd one and I get something like this

75kg/1 m/s = 75

now do I just divide? 75/50 kg = 1.5 m/s ?

 

[Doc Al]

-from what I understand B is the right answer, and If the collision was elastic C would be true, but in this case I think B is the right answer because I know in an isolated collision momentum is always conserved.

You are correct. (The key word in this question is "always".)

with this next question I am having trouble finding the equation I need if anyone can point me in the right direction.

2. A 50 kg swimmer dives horizontally off a 75 kg rowboat. If the
speed of the rowboat
immediately after the swimmer dives off is 1.0 m/s, what speed did
the diver leave the
rowboat?

What's conserved?

 

[wakejosh]

well, the momentum.

ive been trying to figure out the 2nd one and I get something like this

75kg/1 m/s = 75

now do I just divide? 75/50 kg = 1.5 m/s ?

 

[quasar987]

Yes. Since momentum is conserved, it must be that 75*1 = 50*(speed of the diver).