Conservation of momentum of a bullet question

  • Thread starter llamajuice
  • Start date
  • #1
22
0

Homework Statement


A bullet is shot horizontally into a block suspended by two strings. The bullet remains embedded in the wood and the wood and bullet together suspend upward.
a) Explain why the horizontal momentum of the bullet-wood system is conserved during the collision even though the strings exert tension forces on the wood.
b) If the bullet and wood have masses of m and M respectively, and the bullet has an initial speed of v, derive an algebraic expression for the speed of the bullet and wood immediately after the collision before they swing upward in terms of m, M and v.
c) What law of nature can be used to relate the max vertical height to speed just after the collision?
d) Derive an expression for the max vertical height in terms of m, M, v and g.

The Attempt at a Solution


a) I think it is because as the bullet strikes the wood, there is a force of the bullet acting on the wood and a force of the wood acting on the bullet and those 2 forces together equal the initial force of the bullet so momentum is conserved?

b)P = P'
mvm + MvM = mvm’ + MvM ‘
mvm + MvM = (m + M)v
(mvm + MvM)/(m + M) = v

c) I don't know what law of nature they're talking about here.
d)
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
4,433
8
Law of conservation of energy.
 

Related Threads on Conservation of momentum of a bullet question

Replies
2
Views
2K
Replies
5
Views
5K
Replies
3
Views
3K
Replies
3
Views
1K
Replies
10
Views
3K
Replies
5
Views
2K
Replies
1
Views
2K
Replies
6
Views
492
Replies
3
Views
1K
Top