- #1
I Like Pi
- 91
- 0
Homework Statement
Two billiard balls collide on a horizontal table (assume no friction)). Billiard ball A has a mass of 0.175 kg,travelling at 1.20 m/s [E 40 deg S]. Billiard ball B has a mass of 0.225 kg, traveling at 0.68 m/s [E]. The velocity of billiard ball B after collision is 0.93 m/s [E 23 deg S]. What is the velocity of billiard A after the collision and what is the percentage of kinetic energy lost in the collision?
Homework Equations
P = m*v
The Attempt at a Solution
I believe this is a conservation of momentum problem?
therefore: [tex]P_{i}=P_{f}[/tex]
[tex](mv_{A})_{i}+(mv_{B})_{f}=(mv_{A})_{f}+(mv_{B})_{f}[/tex]
[tex].175*1.20+.225*.68=.175*.93+.225*v_{A}_{f}[/tex]
[tex]v_{A}_{f} = .89 m/s[/tex]
What I am unsure of is how i would find the direction of that velocity... I know it's vector problem, but how would i go about solving this, preferably algebraically?
EDIT: never mind, i found out how to do it using the vertical components
And to solve for % of kinetic energy lost, would I need to do it seperately for each ball? using [tex]\frac{1}{2}mv^{2}[/tex]?
Thanks in advance.
Last edited: