Conservation of momentum velocity problem

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SUMMARY

The discussion centers on the conservation of momentum in a system involving a tube and two fragments, A and B. The user initially believes that the tube gains velocity after the collisions, but is corrected by another participant who explains that the system's momentum remains zero. The key takeaway is that while individual velocities may change, the total momentum of the system, which includes the fragments and the tube, must remain conserved, leading to the conclusion that the tube does not move post-collision.

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  • Understanding of Newton's laws of motion
  • Familiarity with the principle of conservation of momentum
  • Basic knowledge of vector quantities in physics
  • Ability to analyze collision problems in one dimension
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kozis
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Homework Statement are included in the attached image.

I've solved the first two parts, my question is about part c. It makes more sense for me to think that the tube has gained some velocity after the collisions and moves to one direction. Probably on the left because the velocity gained from fragment A is bigger than B. But the answer provided says that the velocity should be zero because nothing moves inside the tube and the system's momentum is zero. can someone please explain this to me? I really don't get it. As I mentioned before my thinking is that at first tube gains some velocity after fragment A collides on it and that after collision of fragment B,tube will still be moving with less velocity.
 

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kozis said:
It makes more sense for me to think that the tube has gained some velocity after the collisions and moves to one direction. Probably on the left because the velocity gained from fragment A is bigger than B.
What counts is the momentum, not just the velocity. And the fragments have equal and opposite momenta.
 
Ok I see now.. Thank you for your quick reply.
 

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