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Conservation of Momentum with angles! T_T

  1. May 8, 2008 #1
    1. The problem statement, all variables and given/known data
    You are playing bocci with your friends. You roll your ball towards your opponent's stationary ball (of equal mass) with a certain speed. After the collision, your ball travels along a path o32 degrees from its original path with a speed of 2.50m/s, while your opponent's ball travels along a path 25 degrees from the original path of your ball. What is the initial velocity of your ball?

    2. Relevant equations
    Conservation of Momentum.
    P1 + P2 = P1' + P2'


    3. The attempt at a solution
    Okay, so i tried doing this solution, first i made a diagram of this scenario, but i am not too sure if i drew this correctly. T_T please help me. Here is my attempt of the solution.

    So we are trying to find v1

    v1 = ?
    Pi - initial momentum
    Pf - final momentum

    Pi = Pf
    m1v1 + m2v2 = m1v1' + m2v2'
    m1v1 + 0 = m1v1' + m2v2'

    .... this is far as i have gone, i was not too sure what to place as my v2' ...
    and the masses? hm.... :(. Please Help! T_T
     

    Attached Files:

  2. jcsd
  3. May 8, 2008 #2

    rock.freak667

    User Avatar
    Homework Helper

    (can't see your attachment as yet).

    If they had collided elastically I could have suggested an easier way to find it (I think)

    But what you could do is split the velocities at the angles into vertical and horizontal components and then use conservation of momentum in both the vertical and horizontal directions.
     
  4. May 8, 2008 #3
    I have finished solving this question, thank you for your help!
     
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