Conservation of Momentum law problem

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Homework Help Overview

The discussion revolves around a problem involving the conservation of momentum and energy in a collision scenario with two masses, m1 and m2, having specified velocities. Participants are exploring the relationships between these variables and the equations governing their interactions.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to apply the conservation of momentum and conservation of energy equations to derive relationships between the final velocities after collision. There are questions about the correctness of the momentum equation and how to manipulate the equations to express one variable in terms of another.

Discussion Status

Some participants have provided guidance on how to relate the variables through substitution, while others express confusion regarding the setup and the example given by the teacher. There is an ongoing exploration of the implications of the equations and their components.

Contextual Notes

Participants are grappling with the interpretation of the equations and the assumptions underlying the problem, including the initial conditions of the system and the nature of the collision.

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Homework Statement


m1= 3kg m2= 6kg
v1 = 5m/s v2= 2m/s
d = 3m
DIAGRAM : http://gyazo.com/17b3126726b109256a35f65b86708bb0

Homework Equations


Conservation of momentum:
m1+v1 = m1v1'+m2v2'

Conservation of elastic:
m1v1^2+m2v2^2 = m1v1'^2+m2v2'^2

The Attempt at a Solution


Now my attempt was use both equations & the answers I've gotten so far are 27=3v1'+6v2'(for conservation of momentum) & the 2nd one I've got for the conservation of elastic is 99= 3v1'^2 + 6v2'^2 since they will collide at some point. The only thing I'm stuck at is what to do next afterwards. My teacher has done a similar question but I can never understand how he did it.
 
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Is the conservattion of momentum law correct ??!
I mean Is it llike what you wrote or like the following
m1v1 + 0 = m1v1+m2v2

Zero indecates that the momentum is zero because the vilocity of the second ball before collision is zero ..
Am I right ..
 
Sorry v1 has a value
so the will be
m1v1 +m2v2 = m1v1+m2v2
 
Im just stuck because the example that my teacher gave was like "50=2(10-3v2'/2)^2+3v2'^2" that bracket part confuses me
 
Try to equte the two equation or write v1 in term of v2..
 
Maged Saeed said:
Try to equte the two equation or write v1 in term of v2..
WOW WHAT THE ****, OK I DID THAT ONE BEFORE. Its this right? " V1+V1' = V2+V2'" but can u explain why that is that cus it made some sense to me. & I showed my friend this process but, she said it made no sense so.
 
I think your teacher has written v1 in term of v2
try to do so from the first equation your v1 will be (27 - 6 v2) /3 which is 9-2v2

It seems reasonable
;)
 
Maged Saeed said:
I think your teacher has written v1 in term of v2
try to do so from the first equation your v1 will be (27 - 6 v2) /3 which is 9-2v2

It seems reasonable
;)
but why is that though? :( pls
 
Because v1 and v2 are related by these two equations and their value must satisfy both of them
so we make this substitution
I hope that I understand your question and answer it ..
o_O
 
  • #10
Maged Saeed said:
Because v1 and v2 are related by these two equations and their value must satisfy both of them
so we make this substitution
I hope that I understand your question and answer it ..
o_O
alright thaanks dawg really appreciate that, last question in the example he gave so the last line was 50-50 = -30v2'+7.5v2'^2
the left side what if it wasnt 0
 
Last edited:
  • #11
If the lift side isn't zero move it to the right side and solve the quadratic equation..

By the way what does dawg mean in your last comment
o_O
 
  • #12
Maged Saeed said:
If the lift side isn't zero move it to the right side and solve the quadratic equation..

By the way what does dawg mean in your last comment
o_O
means like dude lol kids these days
 

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