Consistent enumeration on a poset

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SUMMARY

The discussion centers on the concept of consistent enumeration in partially ordered sets (posets). A consistent enumeration is defined as a function f: P -> N such that if a < b, then f(a) < f(b). The confusion arises regarding whether this function must be an injection, particularly when considering elements that are not comparable. It is clarified that in linearly ordered sets, the function is indeed an injection, but this does not hold true for posets where elements may not be comparable.

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  • Understanding of posets and their properties
  • Familiarity with functions and injections in mathematics
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  • Basic concepts of topological sorting and linear extensions
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farleyknight
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Hey all,

I've got a copy of Schaum's outline of Discrete Mathematics, and in the section on ordered subsets and lattices, it includes the definition of a consistent enumeration:

Succinctly, given a poset P, there exists f: P -> N, so that if a < b then f(a) < f(b)

http://books.google.com/books?id=6A...meration"&source=gbs_search_s&cad=0#PPA447,M1

However, I had this in my notes that it was not just a function but an injection. Of course, looking at it again, I didn't consider the case of a || b. I don't know where I got this from and now I'm slightly confused. The closest I could find to this definition was a linear extension and topological sorting, which are slightly different.

Does anyone know this topic well enough to dispell my confusion?

Thanks,
- Farley
 
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IF P is linearly ordered, then "if a< b then f(a)< f(b)" implies that f is an injection. However, in a partially ordered set, it may happen that a and b are "not comparable" (i.e. none of a= b, a< b, nor b< a is true) in which case f(a) may equal f(b) and so f is not necessarily an injection.
 

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